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3 years ago

Which element in Figure 2 is a transition metal? Which is a noble gas?

Physics

1 answer:

quester [9]3 years ago

5 0

<span>V is the transition metal. He is the noble gas. The periodic chart is arranged with metals on the left and non-metals on the right and the noble (non-reactive) gases form the rightmost column. The transition metals are the group of elements from columns 3 through 12. Although a strict definition of transition metals is those elements that have an incomplete d sub-shell, in which case column 12 is excluded since zinc, cadmium, and mercury do have complete d sub-shells. With that in mind, since the element V is the only element listed in the range of a transition metal, that's the answer. And since He is the only element listed in the noble gas column, that too is the answer.</span>

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Two identical 0.200kg mass are pressed against opposite ends of a light spring of force constant 1.75N/cm compressing the spring

arlik [135]

This type of a problem can be solved by considering energy transformations. Initially, the spring is compressed, thus having stored something called an elastic potential energy. This energy is proportional to the square of the spring displacement d from its normal (neutral position) and the spring constant k:

$E_p=\frac{1}{2}kd^2= \frac{1}{2}175\frac{N}{m}\cdot 0.37^2m^2=11.98J$

So, this spring is storing almost 12 Joules of potential energy. This energy is ready to be transformed into the kinetic energy when the masses are released. There are two 0.2kg masses that will be moving away from each other, their total kinetic energy after the release equaling the elastic energy prior to the release (no losses, since there is no friction to be reckoned with).

The kinetic energy of a mass m moving with a velocity v is given by:

$E_k = \frac{1}{2}mv^2$

And we know that the energies are conserved, so the two kinetic energies will equal the elastic potential one:

$E_p = 2E_k=mv^2$

From this we can determine the speed of the mass:

$E_p =mv^2\implies v=\pm \sqrt{\frac{E_p}{m}}=\pm\sqrt{\frac{11.98J}{0.2kg}}=\pm 7.74\frac{m}{s}$

The speed will be 7.74m/s in in one direction (+), and same magnitude in the opposite direction (-).

4 0

3 years ago

A student, along with her backpack on the floor next to her, are in an elevator that is accelerating upward with acceleration a.

Anna007 [38]

Answer:

$\mu_k = \frac{2(vt - L)}{(g + a) t^2}$

Explanation:

As we know that backpack is kicked on the rough floor with speed "v"

So here as per force equation in vertical direction we know that

$N - mg = ma$

so normal force on the block is given as

$N = mg + ma$

now the magnitude of kinetic friction on the block is given as

$F_f = \mu N$

$F_f = \mu (mg + ma)$

now when bag is sliding on the floor then net deceleration of the block due to friction is given as

$a = - \frac{F_f}{m}$

$a = -\mu_k(g + a)$

now we know that bag hits the opposite wall at L distance away in time t

so we have

$d = v t + \frac{1}{2}at^2$

$L = vt - \frac{1}{2}(\mu_k)(g + a) t^2$

$\mu_k = \frac{2(vt - L)}{(g + a) t^2}$

8 0

3 years ago

You use 35 J of energy to move a 7.0 N object. How far did you move it?

Lesechka [4]

The object has been moved by 5 m

Explanation:

The work done by a force when moving an object (which is equal to the energy used to move the object) is given by

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In this problem, we have

W = 35 J is the work done

F = 7.0 N is the magnitude of the force

$\theta=0^{\circ}$ , assuming the force is applied parallel to the direction of motion of the object

Therefore, we can solve the formula for d to find the displacement of the object:

$d=\frac{W}{F cos \theta}=\frac{35}{(7)(cos 0)}=5 m$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

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6 0

4 years ago

If all the mechanical energy is converted into heat that stays in the water. How much of a rise in temperature occurs in a 90.0

vodka [1.7K]

If all the mechanical energy is converted into heat that stays in the water. 0.21˚C rise in temperature occurs in a 90.0 m waterfall.

The total kinetic and potential energy is known as mechanical energy. According to the principle of mechanical energy conservation, mechanical energy is constant in an isolated system when only conservative forces are acting on it.

The mechanical energy of water is converted into heat energy.

P.E = mgh = m x 9.8 x 90.0

P.E = 882 m.

Let rise in temperature θ

Heat energy = mass × specific heat × temperature change

Heat energy = m x s x θ

specific heat = 4186 J/(Kg *˚C)

m x s x θ = 882 m

m x 4186 x θ = 882 m

θ = 0.21˚C.

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2 years ago

Which statement best describes the interaction between earths magnetosphere and solar wind

Vlad [161]

The solar wind is deflected by the magnetosphere

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4 years ago

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