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Zolol [24]
3 years ago
6

Which element in Figure 2 is a transition metal? Which is a noble gas?

Physics
1 answer:
quester [9]3 years ago
5 0
<span>V is the transition metal. He is the noble gas. The periodic chart is arranged with metals on the left and non-metals on the right and the noble (non-reactive) gases form the rightmost column. The transition metals are the group of elements from columns 3 through 12. Although a strict definition of transition metals is those elements that have an incomplete d sub-shell, in which case column 12 is excluded since zinc, cadmium, and mercury do have complete d sub-shells. With that in mind, since the element V is the only element listed in the range of a transition metal, that's the answer. And since He is the only element listed in the noble gas column, that too is the answer.</span>
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Answer:

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Explanation:

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What is the impulse of a 3 kg object that starts from rest and moves to 20 m/s?
IrinaK [193]

Answer:

The impulse on the object is 60Ns.

Explanation:

Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.

F = m a

F = m(\frac{v_{2}  - v_{1} }{t})

⇒     Ft = m(v_{2} - v_{1})

where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, v_{1} is its initialvelocity and v_{2} is the final velocity of the object.

Therefore,

impulse = Ft = m(v_{2} - v_{1})

From the question, m = 3kg, v_{1} = 0m/s and v_{2} = 20m/s.

So that,

Impulse = 3 (20 - 0)

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The impulse on the object is 60Ns.

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What kind of weather is signaled by cumulus clouds
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An object is placed 4.0 cm to the left of a convex lens with a focal length of +8.0 cm . Where is the image of the object?
Serjik [45]

The image of the object is 8cm to the left of the lens (D)

<h3></h3>

What is the image of an object?

The image of an object is said to be the location where light rays from that object intersect with a mirror by reflection.

It is calculated thus:

1÷v = 1÷f - 1÷u

<h3>How to calculate the image of an object</h3>

From the formula

1÷v = 1÷f - 1÷u

<h3>Where </h3>

V = image distance fromthe object

U = object

f = focal length

Substitute the values

1÷v = 1÷8 - 1÷ 4

1÷v = - 1÷8

Make v the subject of formula

v = -8cm

Therefore, the image of the object is 8cm to the left of the lens (D)

Learn more on focal length here:

brainly.com/question/25779311

#SPJ1

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Calculate the potential energy of a 4 kg cat crouched 3 meters off the ground
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