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makkiz [27]
2 years ago
7

An iron nail floats in mercury and sinks in water. explain why?​

Physics
1 answer:
denpristay [2]2 years ago
8 0

Answer:

because density of iron is more than that of water but less then that of Mercury

<em><u>hop</u></em><em><u>e</u></em><em><u> it's</u></em><em><u> helpful</u></em>

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Ions form bonds by __________ electrons.
goldenfox [79]
I would say it’s “donating” so giving up...
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2 years ago
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A cyclotron with a magnetic field of 0.47 t is designed to accelerate protons in a circle with a radius 0.68 m. What is the angu
Ghella [55]

The angular frequency of the cyclotron is 0.07 x 10^{8}Hz.

<h3>What is angular frequency?</h3>
  • Angular frequency, abbreviated "ω" is a scalar measure of rotation rate in physics.
  • It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.
<h3>What is cyclotron?</h3>

The cyclotron device is made to accelerate charge particles to extremely high speeds by applying crossed electric and magnetic fields.

<h3>Calculation of angular frequency:</h3>

Given,

B = 0.47 T

r = 0.68

mass of proton = 1.6x10^{-27}

q = 1.6 x 10^{-19}

so, the frequency is:

f = qB/2\pim

f = 1.6 x 10^{-19} x 0.47/2x3.14x1.6x10^{-27}

f = 0.07 x 10^{8}

Hence, the angular frequency of the cyclotron is  0.07 x 10^{8}Hz.

Learn more about angular frequency here:

brainly.com/question/14244057

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7 0
1 year ago
Kendall has empty graduated cylinder with markings and an identical graduated cylinder partway filled with water. She also has a
Elis [28]
The answer is B.
She can measure the mass of the water, marble and the graduated cylinder with the balance.
The volume of the water can be shown on the marked graduated cylinder, the volume of the marble can be measured by the volume difference of the water before and after the marble is put in.
4 0
2 years ago
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Two spherical conductors are separated by a distance much larger than either of their radii. Sphere A has a radius of 11.5 cm an
bonufazy [111]

Explanation:

As the given spheres are connected by a thin wire so, the potential on the spheres are the same.

          \frac{q_{1}}{r_{1}} = \frac{q_{2}}{r_{2}} ......... (1)

Hence, total charge will be as follows.

              q_{1} + q_{2} = Q = -95.5 nC .......... (2)

Using the above two equations, the final equation will be as follows.

          q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}

and,    q_{1} = \frac{Qr_{1}}{r_{1} + r_{2}}

Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.

          q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}

                     = \frac{-95.5 \times 74.4 cm}{(11.5 + 74.4) cm}

                     = 82.714 nC

Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.

                       

5 0
3 years ago
A power boat pulls a water skier 2.6 km maintaining a
Luba_88 [7]

Answer:

W = 650 [kJ]

Explanation:

The definition of work is denoted by the product of force by the distance traveled by the body, this distance traveled corresponds to the direction of the force.

In this case we have:

d = distance = 2.6[km] = 2600 [m]

F = force = 250 [N]

W = F*d = 250 * 2600 = 650000 [J] or 650 [kJ]

7 0
3 years ago
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