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const2013 [10]
4 years ago
11

Magma can partially crystallize at depth and then rise to shallow depths where the remaining magma solidifies. the early-formed

crystals are ____________ and the texture is ____________ . in ____________ very large crystals can grow, forming ____________ . magma that cools in ____________ has a relatively short time to cool and so forms ____________ , but not volcanic glass. in ____________ , magma cools at a slow rate, allowing the formation of ____________ .
Physics
1 answer:
Murljashka [212]4 years ago
7 0
Magma can partially crystallize at depth and then rise to shallow depths where the remaining magma solidifies. the early-formed crystals are phenocrysts and the texture is porphyritic. in Lava or near the earth surface,very large crystals can grow, forming intrusive rocks or volcanic rocks . magma that cools in <span>shallow magma chambers </span> has a relatively short time to cool and so forms <span>fine grained rocks </span>, but not volcanic glass. in deep magma chamber, magma cools at a slow rate, allowing the formation of extrusive or plutonic rock .
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Find the mass of an object that has 147J of potential energy sitting on a 3m ledge. I don’t understand this. Help quick! ;^;
siniylev [52]

Answer: m = 5 kg

Explanation: To solve for the mass of the object we will use the formula of Potential energy

PE = mgh. Derive for mass, so the formula will be

m= PE / gh

m = 147 J / 9.8 m/s² ( 3 m )

= 5 kg

3 0
3 years ago
Which gases are found in the atmospheres of the gas giants?
givi [52]

Answer:

Hope this helps u pls mark me brainlist

Explanation:

The gas giants have atmospheres that are mostly hydrogen and helium. All four planets rotate relatively rapidly – while Earth spins once on its axis every 24 hours, Saturn spins once every 10 hours. Like Earth, all the gas giants have wind bands. These are seen as east-west stripes.

6 0
2 years ago
A 0.100 kg ball hangs from a spring of negligible mass. When the ball is hung on the spring and is at rest, the spring is stretc
anzhelika [568]

Answer:

a) 4.9 N/m

b) 1.4 m/s

c) 0.225 s

Explanation:

Hooke's law states that

F = k * Δx

Where

F: force applied to a spring

k: constant of the spring

Δx: elongation of the spring

The force applied in this case is the weight of the ball, this is

P = m * g = 0.1 kg * 9.81 m/s^2 = 0.981 N

Rearrainging Hooke's law:

k = F / Δx

k = 0.981 / 0.2 = 4.9 N/m

If the ball is pulled down the spring will acquire some potential energy, when it is released, the potential energy will be released as kinetic energy on the ball

Ec = \frac{1}{2} * m * v^2

Elastic potential energy is:

U = \frac{1}{2} * k * \Delta x^2

The energy gained from the 0.2m pull will be turned into kinetic energy

Ec = U

Therefore:

\frac{1}{2} * m * v^2 = \frac{1}{2} * k * \Delta x^2

Rearranging:

v^2 = \frac{k}{m} * \Delta x^2

v = \Delta x * \sqrt{\frac{k}{m}}

v = 0.2 * \sqrt{\frac{4.9}{0.1}} = 1.4 m/s

After being released the ball will oscillate at the natural frequency of the system, which is

f = \frac{1}{2 * \pi} * \sqrt{\frac{k}{m}}

And the period will be:

T = 2 * \pi * \sqrt{\frac{m}{k}}

The period in this case is:

T = 2 * \pi * \sqrt{\frac{0.1}{4.9}} = 0.9 s

The ball will move up and down taking T time to complete a cycle, the movement from the stretched position to the equilibrium position takes T/4 = 0.225 s

8 0
3 years ago
A system consists of two spheres, of mass m and 2m, connected by a rod of negligible mass, as shown above. The system is held at
Svetradugi [14.3K]

Answer:

Rod will remain horizontal all the time after release.

Explanation:

This is because net torque on the rod about any point in space is zero.

Let assume that distance between the two masses m and 2m is L.

Also m is situated at origin and in positive XY direction.

Then , Center of mass is at L(\frac{mx_{1}+2mx_{2}} }{m +2m})

 COM =\frac{2L}{3}

So let us calculate net torque about hinged point which COM.

  • Torque because of hinge force is zero because it passes from that point itself.
  • Torque on 2m mass is 2mg(L/3) in nenegative Z direction.
  • Torque on m mass is mg(2L/3) in positive Z direction.

As both torque are equal and opposite then net torque =0.

Thus it got balanced.

8 0
3 years ago
Does blowing room-temperature air over an ice block heat it because of convection
Mandarinka [93]

Yes

Explanation:

Blowing a room-temperature air over an ice block will heat it because of convection.

Convection is one of the heat transfer modes that occurs in fluids.

  • In convection, a hot and lighter fluid replaces a denser and cold fluid.
  • It involves the actual motion of the particles of the medium.
  • In this analogy, the blowing room-temperature is hot and lighter.
  • It will replace the air close to the ice block body that is cold and denser
  • As the hot air comes near the ice block, it loses some of its heat and warms the cold ice.
  • In turn, the air becomes colder and moves away.
  • This is simple convection in action.

learn more:

Heat transfer by the sun brainly.com/question/1140127

#learnwithBrainly

5 0
3 years ago
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