When an atom becomes electrically charged the number of electrons or protons stops and they are not equal again. The "extra" electron or proton is not balanced by something inside the atom any longer and it starts attracting itself to othet protons or electrons in other atoms.
<h3>What is atomic structure?</h3>
An atomic structure comprises of positively charged nucleus which is surrounded by negatively charged particles called electron and neutron which is neutral charged.
Unlike charges attract each other while like charges repel each other.
Therefore, When an electron is fully charged, the number of electrons will stop to be unequal again.
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Explanation:
- In chemical reactions, chemical changes occur.
- Atoms are simply rearranged and new bonds are formed.
- Chemical reactions are driven by a need for atoms to attain stability in their structure.
- In all chemical reactions, a reactant or reactants gives new product i.e new substances are formed.
- Most these reactions are not easily reversible.
- They are usually accompanied by the release of energy.
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Answer:
White dwarfs are likely to be much more common. The number of stars decreases with increasing mass, and only the most massive stars are likely to complete their lives as black holes. There are many more stars of the masses appropriate for evolution to a white dwarf.
Answer:
The wagon will move to the right.
Explanation:
From the question given above, the following data were obtained:
Force applied to the left (Fₗ) = 10 N
Force applied to the right (Fᵣ) = 30 N
Direction of the wagon =.?
To determine the direction in which the wagon will move, we shall determine the net force acting on the wagon. This can be obtained as follow:
Force applied to the left (Fₗ) = 10 N
Force applied to the right (Fᵣ) = 30 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 30 – 10
Fₙ = 20 N to the right
From the calculations made above, the net force acting on the wagon is 20 N to the right. Hence the wagon will move to the right.
Answer:
- quality factor (Q) = 69.99
- inductor = 1.591 x 10⁻⁴ H
- capacitor = 3.248 x 10⁻¹⁰ F
Explanation:
Given;
resonance frequency (F₀) = 700 kHz
resistor, R = 10 Ohm
bandwidth (BW) = 10 kHz
bandwidth (BW)
make L (inductor) the subject of the formula
make C (capacitor) the subject of the formula
quality factor (Q)
quality factor (Q) = 69.99