1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
const2013 [10]
3 years ago
11

Magma can partially crystallize at depth and then rise to shallow depths where the remaining magma solidifies. the early-formed

crystals are ____________ and the texture is ____________ . in ____________ very large crystals can grow, forming ____________ . magma that cools in ____________ has a relatively short time to cool and so forms ____________ , but not volcanic glass. in ____________ , magma cools at a slow rate, allowing the formation of ____________ .
Physics
1 answer:
Murljashka [212]3 years ago
7 0
Magma can partially crystallize at depth and then rise to shallow depths where the remaining magma solidifies. the early-formed crystals are phenocrysts and the texture is porphyritic. in Lava or near the earth surface,very large crystals can grow, forming intrusive rocks or volcanic rocks . magma that cools in <span>shallow magma chambers </span> has a relatively short time to cool and so forms <span>fine grained rocks </span>, but not volcanic glass. in deep magma chamber, magma cools at a slow rate, allowing the formation of extrusive or plutonic rock .
You might be interested in
A 10.0 cm object is 5.0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and th
fiasKO [112]
Let's use the mirror equation to solve the problem:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where f is the focal length of the mirror, d_o the distance of the object from the mirror, and d_i the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for d_i by using the numbers given in the text of the problem:
\frac{1}{12 cm}= \frac{1}{5 cm}+ \frac{1}{d_i}
\frac{1}{d_i}= -\frac{7}{60 cm}
d_i = -8.6 cm
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
6 0
3 years ago
Read 2 more answers
A heat pump is to be used for heating a house in winter. The house is to be maintained at 70°F at all times. When the temperatur
Anna35 [415]

Answer:

\dot{W_{H} } = 4244.48 Btu/h

Explanation:

Temperature of the house, T_{H} = 70^{0} F

Convert to rankine, T_{H} = 70^{0}+ 460 = 530 R

Heat is extracted at 40°F i.e T_{L} = 40^{0}F  = 40 + 460 = 500 R

Calculate the coefficient of performance of the heat pump, COP

COP = \frac{T_{H} }{T_{H} - T_{L}  } \\COP = \frac{530 }{530 - 500  }\\ COP = \frac{530}{30} \\COP = 17.67

The minimum power required to run the heat pump is given by the formula:

\dot{W_{H} } = \frac{\dot{Q_{H} }}{COP} \\...............(*)

Where the heat losses from the house, \dot{Q_{H} } = 75,000 Btu/h

Substituting these values into * above

\dot{W_{H} } = \frac{75000}{17.67} \\ \dot{W_{H} } = 4244.48 Btu/h

3 0
2 years ago
a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis
KatRina [158]
The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

d = vt = (22 m/s)(12 s) = 264 m

For the west or W direction, we use the equations:
a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
t = 18.33 seconds
d = (22 m/s)(18.33 s) + 0.5(-1.2 m/s²)(18.33 s)²
d = 201.67 m

Thus,
Total Displacement = 264 m +  201.67 m = 465.67 or  approximately 4.7×10² m.
7 0
2 years ago
Car A hits car B (initially at rest and of equal mass) from behind while going 15 m/s Immediately after the collision, car B mov
Mamont248 [21]

Given :

Initial speed of car A is 15 m/s and initial speed of car B is zero.

Final speed of car A is zero and final speed of car B is 10 m/s.

To Find :

What fraction of the initial kinetic energy is lost in the collision.

Solution :

Initial kinetic energy is :

K.E_i = \dfrac{15^2m}{2} + 0\\\\K.E_i = \dfrac{225 m}{2}

Final kinetic energy is :

K.E_f = \dfrac{10^2m}{2} + 0\\\\K.E_f = \dfrac{100m}{2}

Now, fraction of initial kinetic energy loss is :

Loss = \dfrac{\dfrac{225m}{2}-\dfrac{100m}{2}}{\dfrac{100m}{2}}\\\\Loss = \dfrac{125}{100}\\\\Loss = 1.25

Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .

6 0
2 years ago
A car is traveling at 75 m/s. 50 seconds later it is traveling at 25 m/s. What is the car’s acceleration?
scoray [572]

Answer:

a = -1 m/s^2

Explanation:

Vi = 75 m/s

Vf = 25 m/s

t = 50 s

Plug those values into the following equation:

Vf = Vi + at

25 = 75 + 50a

---> a = -1 m/s^2

5 0
3 years ago
Other questions:
  • An outside thermometer reads 57°F. What is this temperature in °C? Round your answer to the nearest whole number.
    9·2 answers
  • What enables humans to see light in the infrared range of the electromagnetic spectrum
    6·2 answers
  • I need help on a it all please
    10·1 answer
  • Describe how the speed of light waves changes when they travel from air into a
    8·2 answers
  • Convert 23 miles into feet.<br> **There are 5280 feet in 1 mile** *
    7·1 answer
  • Using the assembly-line balancing procedure, which of the following is the required cycle time in minutes per unit if the daily
    5·1 answer
  • State keplers law........​
    8·1 answer
  • Help PLEASE
    5·1 answer
  • Kelly Clarkson is running between the Patronas towers in Kuala Lumpur on a tightrope at a speed of 15 m/s. Kelly currently weigh
    9·2 answers
  • 1. The magnitude of the electrostatic force a charge particle exerts on a 5.0nC particle 0.20m away from it is 18N. Find the mag
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!