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blondinia [14]
3 years ago
15

Why is physics important to everyone? Describe 5 applications of physics in everyday life.

Physics
1 answer:
Sedaia [141]3 years ago
4 0

1. Communication

   In early ages people were using letters to communicate between them. Now days instantly we can call one person from anywhere, these are based on optical fiber communication and it is an application of physics.

2. Transportation

  We can travel from place to anther place by aeroplane , these technologies are introduced after advancement in physics.

3. Construction

 Earlier people used to stay in small houses, now days apartments with many number of storeys are built by considering all the forces coming on the structure.

4. Medical Department

 The invention of many equipment increased the health of humans.

5. Weather forecasting

 The prediction of weather considering all the available factors, prediction of natural disasters all are application of physics.

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Which way do the players on the court rotate during a game? What happens if the players serve out of order?
tigry1 [53]

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Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the mete
disa [49]

Answer:

Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the meter stick and carries 1.50 A of current upward. Wire 2 hangs from the 70-cm mark and carries 4.00 A of current downward. Wire 3 is to be attached to the meterstick and to carry a specific current, and we want to attach it at a location that results ineach wire experiencing no net force.

(a) Determine the position of wire 3.

b) Determine the magnitude and direction of current in wire 3

Explanation:

a) F_{net} \text {on wire }3=0

\frac{\mu_0 I_1 I_3}{2 \pi x} = \frac{\mu I_2 I_3}{2 \pi (0.2+x)} \\\\\frac{1.5}{x} =\frac{4}{0.2+x} \\\\0.03+1.5x=4x\\\\x=0.012m\\\\=1.2cm

position of wire = 50 - 1.2

= 48.8cm

b)  F_{net} \text {on wire }1=0

\frac{\mu _0 I_1 I_3}{2 \pi (1.2)} = \frac{\mu _0 I_1 I_2}{2 \pi (20)} \\\\\frac{I_3}{1.2} =\frac{4}{20} \\\\I_3=0.24A

Direction ⇒ downward

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Answer:

Explanation: please see attached file I attached the answer to your question.

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