All categories

3 years ago

Match the element properties with their descriptions

Physics

1 answer:

forsale [732]3 years ago

4 0

1. ability to be pounded into shapes

2. how well a substance flows

3. the mass divided by its volume

4. degree of smoothness

5. ability to dissolve in another substance

6. how shiny a material is

7. ability to be pulled into a wire

You might be interested in

Why is pseudoscience bad?

Dmitrij [34]

Answer:

Because psuedoscience is a collection of beliefs or practices mistakenly regarded as being based on scientific method.

And it is most of the time false

Explanation:

5 0

3 years ago

Determine the final temperature of a gold nugget (mass = 376 g) that starts at 398 K and loses 4.85 kJ of heat to a snowbank whe

m_a_m_a [10]

Answer: Final temperature of a gold nugget will be 297 K

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$q=m\times c\times (T_{final}-T_{initial})$

q = heat released = -4.85 kJ = -4850 J

m = mass of metal = 376 g

$T_{final}$ = final temperature of metal = ?

$T_{initial}$ = initial temperature of metal = 398 K

c = specific heat of metal =

$-4850=376\times 0.128\times (T_{final}-398)$

$(T_{final}-398)=-101$

$(T_{final}=297K$

Thus the final temperature of a gold nugget will be 297 K

6 0

3 years ago

1. Which characteristics of Pop Art are evident in the image? Select all that apply.

Cloud [144]

I think the answer is C

3 0

3 years ago

Read 2 more answers

As the earth rotates, what is the speed of a physics student in Miami, Florida, at latitude 26∘? Ignore the revolution of the ea

ASHA 777 [7]

Answer:

$v =418 m/s$

Explanation:

given,

Radius of earth = 6400 Km

speed of a physics student in Miami, Florida, at latitude 26° = v

time period of rotation = 24 hour = 24 × 3600

= 86400 s

distance = speed × time

$v = \dfrac{distance}{time}$

$v = \dfrac{6400\times cos (26^0)\times 2 \pi }{86400}$

$v =0.41831 Km/s$

$v =418 m/s$

hence, the velocity of the student is equal to $v =418 m/s$

6 0

2 years ago

An 18g bullet is shot vertically into a 10kg block. The block lifts upward 9mm. The bullet penetrates the block in a time interv

stealth61 [152]

Answer:

The initial kinetic energy of the bullet is closest to 491.87 J

Explanation:

Given;

mass of bullet, m₁ = 18g = 0.018kg

mass of block, m₂ = 10kg

height moved by the block, h = 9 mm = 0.009 m

time taken for the bullet to travel through the block, t = 0.001s

let the initial velocity of the bullet = v₁

let the final velocity of the bullet = v₂

Apply the principle of conservation of linear momentum;

initial momentum = final momentum

0.018v₁ = v₂(0.018 + 10)

0.018v₁ = 10.018v₂ -----equation (1)

Apply the law of conservation of energy when the bullet lifts the block through 9mm

mgh = ¹/₂mv₂²

gh = ¹/₂v₂²

v₂² = 2gh

v₂ = √2gh

v₂ = √(2 x 9.8 x 0.009)

v₂ = 0.42 m/s

Substitute in v₂ in equation 1, to determine the initial velocity of the bullet;

0.018v₁ = 10.018v₂

0.018v₁ = 10.018(0.42)

0.018v₁ = 4.208

v₁ = 4.208 / 0.018

v₁ = 233.78 m/s

Now, determine the initial kinetic energy of the bullet;

K.E₁ = ¹/₂m₁v₁²

K.E₁ = ¹/₂(0.018)(233.78)²

K.E₁ = 491.87 J

Therefore, the initial kinetic energy of the bullet is closest to 491.87 J

6 0

3 years ago