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Answer:
The energy E is 1603.008 J.
Explanation:
Given that,
Capacitor = 18.4 μF
Voltage = 13.2 kV
We need to calculate the energy
Using formula of energy
.....(I)
We know that,
Put the value of Q in equation (I)
On integration
Put the value into the formula
Hence, The energy E is 1603.008 J.