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Ipatiy [6.2K]
4 years ago
4

In certain fireworks, potassium nitrate breaks down into potassium oxide, nitrogen, and oxygen. This is an example of a _____ re

action. The opposite process is a _____ reaction.
options for both of the blanks are
A) combustion
B) decomposition
C) replacement
or D) synthesis
Physics
2 answers:
OLga [1]4 years ago
6 0
In certain fireworks, potassium nitrate breaks down into potassium oxide, nitrogen, and oxygen. This is an example of a "Decomposition reaction". <span>The opposite process is a "Synthesis" reaction.

In short, fill your blanks as:
1st blank  </span>→ Option B
2nd blank → Option D

Hope this helps!
BabaBlast [244]4 years ago
5 0

Answer : The correct option for 1st blank is Decomposition and for 2nd blank is Synthesis.

Explanation :

  • Decomposition reaction : This reaction occurs when one bigger molecule decomposes into two or more smaller molecules.
  • Synthesis reaction : This reaction occurs when two or more smaller reactants combine to form a single large product.
  • Combustion reaction : This reaction occurs when a hydrocarbon molecule react with the oxygen molecule to produce carbon dioxide and water.
  • Replacement reaction : This reaction occurs when the more reactive element replaces the less reactive element in a compound.

When potassium nitrate breaks down into potassium oxide, nitrogen, and oxygen that means one bigger molecule decomposes into two or more smaller molecules. So, this an example of a decomposition reaction.

And in the opposite process that means potassium oxide, nitrogen, and oxygen are combined to form potassium nitrate means two or more small reactant combine to form a single large product. So, this an example of synthesis reaction.

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A 1-kg iron frying pan is placed on a stove. The pan increases from 20°C to 250°C. If the same amount of heat is added to a pan
Nesterboy [21]

Answer;

The temperature change for the second pan will be lower compared to the temperature change of the first pan

Explanation;

-The quantity of heat is given by multiplying mass by specific heat and by temperature change.

That is; Q = mcΔT

This means; the quantity of heat depends on the mass, specific heat capacity of a substance and also the change in temperature.

-Maintaining the same quantity of heat, with another pan of the same mass and greater specific heat capacity would mean that the change in temperature would be much less lower.

7 0
4 years ago
How is velocity and instantaneous speed alike
allsm [11]
<span>velocity is defined as the rate of change of displacement irrespective of the length of the path travelled while speed is the average rate of covering distance. but in the liming case where the instantaneous velocity is given as v=dx/dt where dx is the small displacement in a small interval dt, both the speed and velocity have the same magnitude and the direction of velocity is the direction of the tangent to the corresponding displacement-time curve.</span>
5 0
3 years ago
A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?
stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, m_1 = 300\ g = 0.3\ kg

Initial speed of the cart, u_1=1.2\ m/s

Mass of the larger cart, m_2 = 2\ kg

Initial speed of the larger cart, u_2=0

After the collision,

Final speed of the smaller cart, v_1=-0.81\ m/s (as its recolis)

To find,

The speed of the large cart after collision.

Solution,

Let v_2 is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

m_1u_1+m_2u_2-m_1v_1=m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{0.3\times 1.2+0-0.3\times (-0.81)}{2}

v_2=0.301\ m/s

So, the speed of the large cart after collision is 0.301 m/s.

4 0
3 years ago
A car moving 12m east, then 20m west . What is the displacement?
Ludmilka [50]

Answer:

8 m west

Explanation:

If we say east is the +x direction, and west is the -x direction, then the displacement is:

Δx = 12 m + (-20 m)

Δx = -8 m

8 0
3 years ago
PLEASE HELP ME IM ON A TIMER
garri49 [273]

Answer:

Displacement: 6.71 m, Direction: 63.4 degrees north of east

Explanation:

In the attached image we can aprecciate each one of the movements of the parade. Let's say that the parade started from the origin (point (0,0)) then it moves to the east 4 blocks it means now the parade is located at point (4,0).

Then the parade went to the south three blocks, so it moves to the coordinate (4,-3). After this the parade went to the west one block so the new coordinate point is (3, -3).

And finally the movement of the 0 parade was 9 blocks to the north. It means the final point is now (0,9) - (3,-3) = (3,6)

And the displacement will be defined by the folliwing vector operation:

A (0,0) = oi + 0j\\F (3,6) = 3i + 6 j\\Displacement vector = (3-0)i + (6-0)j = 3i + 6j

We know that the magnitude of the displacement vector is defined by the phytagoras theorem

Displacement = \sqrt{(3)^2+ (6)^2} \\Displacement = 6.70

And the angle will be defined by:

tan(beta)=3/6

beta = tan^-1(6/3)

beta = 63.43°

5 0
3 years ago
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