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alina1380 [7]
3 years ago
5

A cabinet weighing 100 N is placed on a floor. The amount of contact area between the cabinet and the floor is 0.5 m2. How much

pressure does the cabinet exert on the floor
Physics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

p = 200Pa

Explanation:

From its definition, the pressure depends on the force exerted on the floor by the cabinet, and the perpendicular area in which it is applied. This is expressed in the formula:

p=\frac{F}{A}

Since the force the cabinet exerts on the floor is its weight, we can use the given values to calculate the pressure exerted on the floor:

p=\frac{100N}{0.5m^{2} } =200Pa

In words, the pressure the cabinet exerts on the floor is 200Pa.

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What are you doing when you’re making sound? A. Causing air molecules to vibrate. B Causing photons to travel. C Causing air pre
Greeley [361]

Answer: A

Causing air molecules to vibrate

Explanation:

Sound is made by vibrations. And it is an energy. When any object vibrates, it causes movement in the air particles. These particles bump into the particles close to them, which makes them vibrate too causing them to bump into more air particles. This movement, called sound waves, keeps going until they run out of energy.

5 0
3 years ago
What is the force of a punch if it accelerates at 0.2m/s2 and has a mass of 2kg?​
OleMash [197]

Answer:

0.4 N

Explanation:

We know ,

  • F = ma
  • F = 0.2 * 2 N
  • F = 0.4N
6 0
3 years ago
a golf ball is hit with a velocity of 30.0 m/s at an angle of 25 degrees about the horizontal. how long is the ball in the air a
Pie
Ok so use trigonometry to work out the vertical component of velocity.

sin(25) =opp/hyp
rearrange to:
30*sin(25) which equals 12.67ms^-1

now use SUVAT to get the time of flight from the vertical component,

V=U+at

Where V is velocity, U is the initial velocity, a is acceleration due to gravity or g. and t is the time.

rearranges to t= (V+u)/a

plug in some numbers and do some maths and we get 2.583s

this is the total air time of the golf ball.

now we can use Pythagoras to get the horizontal component of velocity.

30^2-12.67^2= 739.29
sqrt739.29 = 27.19ms^-1

and finally speed = distance/time

so--- 27.19ms^-1*2.583s= 70.24m

The ball makes it to the green, and the air time is 2.58s 
4 0
3 years ago
A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the
Shkiper50 [21]

Answer:

 ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round  = 144 Kg

angle =  33.2°

moment of inertia

I = \dfrac{1}{2} m R^2

I = \dfrac{1}{2}\times 144 \times 2.75^2

    I = 544.5 kg.m²

torque = force  x radius

τ = 37.7 x  2.75

τ = 103.675 N.m

angular acceleration

\alpha= \dfrac{\tau}{I}

\alpha= \dfrac{103.675}{544.5}

 α = 0.190 rad/s²

now ,

distance = 33.2\times \dfrca{2\pi}{360}

d = 0.579 rad

we know,

using equation of rotational motion

d = \omega t + \dfrac{1}{2}\alpha t^2

0.579 = \dfrac{1}{2}\times 0.190\times t^2

 t = 2.46 s

angular speed

 ω =  α  x t

 ω = 0.19 x 2.46

 ω = 0.467 rad/s

7 0
2 years ago
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s.
77julia77 [94]

Answer:

See Explanation

Explanation:

m1(v1) + m2(v2)

Opposite turns the plus to subtraction.

80(8) - 120(4.0)

60 - 480 = 160 kg m/s to the right

7 0
2 years ago
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