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alina1380 [7]
3 years ago
5

A cabinet weighing 100 N is placed on a floor. The amount of contact area between the cabinet and the floor is 0.5 m2. How much

pressure does the cabinet exert on the floor
Physics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

p = 200Pa

Explanation:

From its definition, the pressure depends on the force exerted on the floor by the cabinet, and the perpendicular area in which it is applied. This is expressed in the formula:

p=\frac{F}{A}

Since the force the cabinet exerts on the floor is its weight, we can use the given values to calculate the pressure exerted on the floor:

p=\frac{100N}{0.5m^{2} } =200Pa

In words, the pressure the cabinet exerts on the floor is 200Pa.

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In your own words, define the following terms. Radiation, Convection, and conduction.
Dafna11 [192]
Radiation: transferred energy
Convection: Transfer of heat
Conduction: transfer of electric charge

3 0
3 years ago
A boat heads directly eastward across a pier at 12 meters per second. If the current in the river is flowing
Trava [24]

Answer: 13 m/s

Explanation: The two vectors form a 5-12-13 right triangle. the magnitude of their resultant is the hypotenuse, which is 13 m/s.

4 0
3 years ago
A closed system consisting of 10 lb of air undergoes a polytropic process from p1 = 75 lbf/in2, v1 = 4 ft3/lb to a final state w
Vitek1552 [10]

Answer:

The polytropic exponent (n) is 1.2

The amount of energy transfer by work is 552.45 Btu

Explanation:

P1V1^n = P2V2^n

P1 = 75 lbf/in^2 = 75 lbf/in^2 × 143.3 in^2/ft^2 = 10,747.5 lbf/ft^2

V1 = 4 ft^3/lb × 10 lb = 40 ft^3

P2 = 20 lbf/in^2 = 20 × 143.3 = 2866 lbf/ft^2

V2 = 12 ft^3/lb × 10 lb = 120 ft^3

(V2/V1)^n = P1/P2

(120/40)^n = 10747.5/2866

3^n = 3.75

ln 3^n = ln 3.75

n ln 3 = ln 3.75

n = ln 3.75/ln 3 = 1.2

W = (P2V2 - P1V1)/1 - n = (2866×120 - 10747.5×40)/1-1.2 = (343,920 - 429,900)/-0.2 = -85,980/-0.2 = 429,900 lbf.ft = 429,900/778.17 Btu = 552.45 Btu

4 0
3 years ago
An object accelerates 1.5m/s2 when a force of 7.0 newtons is applied to it. What is the mass of the object?
Lorico [155]

The mass of an object that accelerates 1.5m/s² when a force of 7.0 newtons is applied to it is 4.67kg.

<h3>How to calculate mass?</h3>

The mass of an object can be calculated by dividing the force applied to the object by its acceleration. That is;

Mass = Force ÷ acceleration

According to this question, an object accelerates 1.5m/s² when a force of 7.0 newtons is applied to it. The mass of the object can be calculated as follows:

Mass = 7N ÷ 1.5m/s²

Mass = 4.67kg

Therefore, the mass of an object that accelerates 1.5m/s² when a force of 7.0 newtons is applied to it is 4.67kg.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

5 0
2 years ago
A powerboat heads due northwest at 14 m/s relative to the water across a river that flows due north at 4.8 m/s. What is the velo
IgorLugansk [536]

Answer: 13.15m/s, N 20.052°W

Explanation: The diagramatic representation of this question has been attached to this answer, please kindly find below because references will be made to it.

Due to the fact that the boat is moving northwest with a speed of 14m/s and the speed of the water flows at 4.8m/s due north, they can be represented using triangular vectors.

From the attachment below.

H = 14m, O= 4.8m and A=?

Using phythagoras theorem, we have that

H² =O² + A²

14² = 4.8² + A²

A² = 14² - 4.8²

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A= √120.96

A= 13.15m

The direction of the vector is gotten by using the fact that

tan θ = O/A

tan θ = 4.8/14

tan θ = 0.3650

θ = tan^-1 (0.3650)

θ= 20.052°

From the attachment, the vector is lying north east west, hence direction is N 20.052° W

3 0
3 years ago
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