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3 years ago

How is velocity and instantaneous speed alike

1 answer:

5 0

<span>velocity is defined as the rate of change of displacement irrespective of the length of the path travelled while speed is the average rate of covering distance. but in the liming case where the instantaneous velocity is given as v=dx/dt where dx is the small displacement in a small interval dt, both the speed and velocity have the same magnitude and the direction of velocity is the direction of the tangent to the corresponding displacement-time curve.</span>

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show mathematically why an 80,000 pound ( 36,000 kg ) big rig taveling 2 mph (0.89 m/s) has the SAME MOMENTUM as a 4,000 pound (

bekas [8.4K]

The momentum value for both Big rig and sport utility vehicle are the same as 16000 pound mph

<u>Explanation:</u>

Given data are as follows

For Big rig, Mass = 80,000 pound (36,000 kg)

velocity = 2 mph (0.89 m/s)

where mph is meter per hour

For sport utility vehicle, Mass = 40,000 pound (1800 kg)

velocity = 40 mph (18 m/s)

The formula to find the Momentum of an object is

Momentum = Mass × Velocity (Kilogram meter per second)

Momentum for Big rig = 80,000 × 2 (pound mph)

= 1,60,000 pound mph

Momentum for sport utility vehicle = 4000 × 40 (pound mph)

= 1,60,000 pound mph

Hence it is mathematically proved that

The momentum of big rig = The momentum of sport utility vehicle

1,60,000 pound mph = 1,60,000 pound mph

3 0

4 years ago

Hii gm eveyone hope you have a good day!!!!

SSSSS [86.1K]

Answer:

i hope you have one too

Explanation:

4 0

2 years ago

Read 2 more answers

I’ll hand out that gawk gawk hand twist vacuum seal combo 30000 to whoever answers this

Karolina [17]

It’s attract
Now give that Gawk Gawk hand twist vacuum seal combo 30000 playa

8 0

3 years ago

Read 2 more answers

A guitar string of length L = 0.79 m is oriented along the x-direction and under a tension of T = 74 N. The string is made of st

Orlov [11]

Answer:

74 N

Explanation:

T = Tension in the string = 74 N

$\rho$ = Density of the steel = 7800 kg/m³

A = Area = $\pi r^2$

r = Radius = $8.5\times 10^{-4}\ m$

Linear density is given by

$\mu=\rho A\\\Rightarrow \mu=7800\times \pi (8.5\times 10^{-4})^2\\\Rightarrow \mu=0.0177\ kg/m$

The linear density is 0.0177 kg/m

Velocity is given by

$v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow v=\sqrt{\dfrac{74}{0.0177}}\\\Rightarrow v=64.65903\ m/s$

The velocity of the wave on the guitar string is 64.65903 m/s

8 0

3 years ago

The sports car has a mass of 1.5 Mg Mg and a center of mass at G. Determine the shortest time it takes for it to reach a speed o

mezya [45]

Answer:

$\Delta t = 17.041\,s$

Explanation:

The figure of the problem is included below as attachment. The equations of equilibrium are presented below:

$\Sigma F_{x} = -\mu\cdot N_{1} = m\cdot a$

$\Sigma F_{y} = N_{1} + N_{2} - m\cdot g = 0$

$\Sigma M_{G} = N_{1}\cdot x_{1} - N_{2}\cdot x_{2} - \mu\cdot N_{1}\cdot y_{1} = 0$

The system of equations are:

$-0.2\cdot N_{1} = (1500\,kg)\cdot a$

$N_{1} + N_{2} - (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}}\right) = 0$

$N_{1} \cdot [(0.75\,m)-0.2\cdot (0.35\,m)] - N_{2}\cdot (1.25\,m) = 0$

The solution of the system is:

$N_{1} = 9780.918\,N$ , $N_{2} = 4929.582\,N$ and $a = - 1.304\,\frac{m}{s^{2}}$

The shortest time to reach a speed of 80 km/h is:

$\Delta t = \frac{22.222\,\frac{m}{s}-0\,\frac{m}{s}}{1.304\,\frac{m}{s^{2}} }$

$\Delta t = 17.041\,s$

7 0

4 years ago