Complete Question
A system consists of a disk of mass 2.0 kg and radius 50 cm upon which is mounted an annular cylinder of mass 1.0 kg with inner radius 20 cm and outer radius 30 cm (see below). The system rotates about an axis through the center of the disk and annular cylinder at 10 rev/s.
(a) What is the moment of inertia of the system
(b) What is its rotational kinetic energy? axis 50 cm 30 cm 20 cm
Answer:
a)
b)
Explanation:
From the question we are told that:
Mass
Disk Radius
Mass of annular cylinder
Inner Radius of cylinder
Outer Radius of cylinder
Angular Velocity
Generally the equation for moment of inertia is mathematically given by
Generally the equation for Rotational Kinetic Energy is mathematically given by
Answer:
I need to talk to somone about my confusing love life
Explanation:
Information provided:
Length of wire, L = 320 m
Current through the wire, I = 120 Amps
Earth's magnetic field acting on the wire, B = 5.0*10^-5 T
Angle at which the magnetic field acts, Ф = 60°
By definition;
Force on the wire, F = LBI Sin Ф
Substituting;
F = 320*5*10^-5*120*Sin 60 = 1.663 N
Answer:
29.4 J
Explanation:
gravitational potential energy =mgh
Where m is the mass h is the height about ground
and g the acceleration due to gravity
g=9.8ms−2
Hence 2⋅1.5⋅9.8
=29.4 J
Use the value of g you have been taught to use, some people advise using 9.8 or 9.81 but some use 10