Complete Question
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.)
mm/s
Answer:
The drift velocity is 
Explanation:
From the question we are told that
The current on the copper is 
The cross-sectional area is 
The number of copper atom in the wire is mathematically evaluated
Where 
is the density of copper with a value 
is the Avogadro's number with a value 
Z is the molar mass of copper with a value 
So
Given the 1 atom is equivalent to 1 free electron then the number of free electron is
The current through the wire is mathematically represented as
substituting values
=>
Answer:
<em> 3980.89 ohms</em>
Explanation:
The capacitive reactance is expressed as;
f is the frequency
C is the capacitance of the capacitor
Given
f = 60H
C = C1+C2 (parallel connection)
C = 15μF + 25μF
C = 40μF
C = 
Substitute into the formula:
<em>Hence the total capacitive reactance is 3980.89 ohms</em>
Velocity is defined as a change in position.
F=MA
F is force
M is mass
A is acceleration
F=MA
F=(7.5 kg)(8.3 m/s^2)
F=62.25 N (newton- SI unit for force)
Hope this helps
Answer:
Yes , i also need answer
Explanation:
n earthquake emits both P-waves and S-waves that travel at different speeds through the Earth. A P-wave travels at 9 000 m/s and an S-wave at 4 000 m/s. If P-waves are received at a seismic station 34.0 s before an S-wave arrives, how far is the station from the earthquake center
