The electrical force acting on a charge q immersed in an electric field is equal to

where
q is the charge
E is the strength of the electric field
In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
Answer:
Answer is D. 8.04 x 10^4 J
Explanation:
1. D
2. A
3. D
4. B
5. C
6. B
7. D
8. C
9. B
10. D
All correct i promise you that