The molar mass of this gas is 92.3 g/mol
Calculation
By use ideal gas equation PV =nRT where
n=mole p=pressure V= volume R = gas constant T= temperature
n = mass /molar mass(MM)
substitute in the equation
PV =(mass/MM)RT
mass = density x volume(V)
Therefore PV =(density xV/ MM) xRT
divide both side by by V
P= (density/Mm) xRT
making MM the subject of the formula
MM = densityPRT
At STP = P= 1 atm, R= 0.0821 L.atm/Mol.k T = 273 K
MM is therefore = 4.12 g/l x 1 atm x 0.081 L.atm/mol.k x 273 K = 92.3 g/mol
Your answer would be D you welcome !
The given question is incomplete. The complete question is :
This is the chemical formula for carvone (the chemical that gives spearmint its flavor) 
: An organic chemist has determined by measurements that there are 27.3 moles of carbon in a sample of carvone. How many moles of oxygen are in the sample
Answer: 2.73 moles of oxygen are there in the sample.
Explanation:
The chemical formula of carvone is .
This means:
When 10 moles of carbon are there in carvone , 1 mole of oxygen is there in carvone
Thus for 27.3 moles of carbon in carvone , 
mole of oxygen is there in carvone.
Thus 2.73 moles of oxygen are there in the sample.
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