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2 years ago

1. A gas has a volume of 50.0 mL at a temperature of -73°C. What volume

Chemistry

1 answer:

Anton [14]2 years ago

3 0

This is your answer:

-13 degrees C

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Determine the molar solubility for Cr(OH)3 Ksp = 6.3x10^-31 ....

r-ruslan [8.4K]

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2 years ago

Which of the following processes does not facilitate containment?

Marta_Voda [28]

Enrichment of uranium-235 is done. Hence, option A is correct.

<h3>What is the meaning of containment?</h3>

The act, process, or means of keeping something within limits the containment of health costs.

Enrichment is a process of increasing the proportion of fissile isotope found in uranium ore (represented by the symbol 'U') to make it usable as nuclear fuel or the compressed, explosive core of nuclear weapons.

Hence, option A is correct.

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7 0

1 year ago

Can y'all help me with number 4

astraxan [27]

I think the answer is A but i'm not sure

6 0

3 years ago

Read 2 more answers

4.41 g of propane gas (C3H8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below

gayaneshka [121]

Answer : The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

$q_{rxn}=-q_{cal}$

$q_{cal}=c_{cal}\times \Delta T$

where,

$q_{rxn}$ = heat released by the reaction = ?

$q_{cal}$ = heat absorbed by the calorimeter

$c_{cal}$ = specific heat of calorimeter = $97.1kJ/^oC=97100J/^oC$

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=(27.282-25.000)=2.282^oC$

Now put all the given values in the above formula, we get:

$q_{cal}=(97100J/^oC)\times (2.282^oC)$

$q_{cal}=221582.2J=221.6kJ$

As, $q_{rxn}=-q_{cal}$

So, $q_{rxn}=-221.6kJ$

Thus, the heat of the reaction is -221.6 kJ

6 0

2 years ago

What would the total mass of a 4.9 mole sample of Barium (Ba) be if its Molar Mass is 137g?

Aleksandr-060686 [28]

Answer:

m = 671 grams

Explanation:

Given that,

No of moles, n = 4.9

Molar mass of Barium, M = 137 g

Mass divided by molar mass is equal to no of moles. It can be given by the formula as follows :

$n=\dfrac{m}{M}\\\\m=n\times M\\\\m=4.9\times 137\\\\m=671.3\ g$

m = 671 grams

So, the total mass of the sample of Barium is 671 grams.

8 0

2 years ago