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attashe74 [19]
2 years ago
8

The predicted yield for a reaction was 10g of product. If the percentage yield for this reaction was 50%, how much product was f

ormed?​
Chemistry
1 answer:
Pachacha [2.7K]2 years ago
7 0

The quantity of the product that was formed was 5g

From the question,

We are to determine the quantity of product formed. That is, the actual yield.

Using the formula

Percentage \ yield =\frac{Actual \ yield}{Theoretical\ yield} \times 100\%

From the given information

Theoretical yield = 10g

Percentage yield = 50%

Putting the parameters into the formula, we get

50\% = \frac{Actual\ yield}{10} \times 100\%

Then,

50\% = Actual\ yield \times 10\%

∴ Actual yield = \frac{50\%}{10\%}

Actual yield = 5g

Hence, the quantity of the product that was formed was 5g

Learn more here: brainly.com/question/17127987

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Calculate the mass of that n = 2.65\; \rm mol of \rm Li_3PO_4 formula units:

\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}.

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