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attashe74 [19]
2 years ago
8

The predicted yield for a reaction was 10g of product. If the percentage yield for this reaction was 50%, how much product was f

ormed?​
Chemistry
1 answer:
Pachacha [2.7K]2 years ago
7 0

The quantity of the product that was formed was 5g

From the question,

We are to determine the quantity of product formed. That is, the actual yield.

Using the formula

Percentage \ yield =\frac{Actual \ yield}{Theoretical\ yield} \times 100\%

From the given information

Theoretical yield = 10g

Percentage yield = 50%

Putting the parameters into the formula, we get

50\% = \frac{Actual\ yield}{10} \times 100\%

Then,

50\% = Actual\ yield \times 10\%

∴ Actual yield = \frac{50\%}{10\%}

Actual yield = 5g

Hence, the quantity of the product that was formed was 5g

Learn more here: brainly.com/question/17127987

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What is the molarity of a solution in which 25.3 grams of potassium bromide is dissolved in 150. mL of solution?
irga5000 [103]

Answer:

~1.417M

Explanation:

Molarity=(number of moles of solute)/(litres of solution)

In this case, we need to find moles of potassium bromide.

Mass=25.3g

Molar mass= 119g/mol

moles=(mass/molar mass)

        =(25.3)/(119)

        =0.2126moles of potassium bromide

Molarity=(0.2126)/(150/1000)

       ~1.417M

Hope this helps:)

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3 years ago
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At 20.°C, a 1.2-gram sample of Mg ribbon reacts rapidly with 10.0 milliliters of 1.0 M HCl(aq). Which change in conditions would
Pavlova-9 [17]

Answer: (2) decreasing the concentration of HCl(aq) to 0.1 M

Explanation: Rate of a reaction depends on following factors:

1. Size of the solute particles: If the reactant molecules are present in smaller size, surface of particles and decreasing the size increases the surface area of the solute particles. Hence, increasing the rate of a reaction.  

2. Reactant concentration: The rate of the reaction is directly proportional to the concentration of reactants.

3. Temperature: Increasing the temperature increases the energy of the molecules and thus more molecules can react to give products and rate increases.

(1) Increasing the initial temperature to 25°C will increase the reaction rate.

(2) Decreasing the concentration of HCl(aq) to 0.1 M will decrease the reaction rate due to lesser concentration.

(3) Using 1.2 g of powdered Mg will increase the reaction rate due to large surface area.

(4) Using 2.4 g of Mg ribbon will increase the reaction rate due to high concentration of reactants.

7 0
3 years ago
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Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this
maw [93]

Answer:  d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g) \Delta H=+1411.1kJ

Reversing the reaction, changes the sign of \Delta H

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\Delta H=-1411.1kJ

On multiplying the reaction by \frac{1}{2} , enthalpy gets half:

0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol

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The element carbon (C) is most likely to form covalent bonds with the element
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