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3 years ago

1. Real numbers that cannot represent as a quotient of two integers are ____ numbers.

Mathematics

1 answer:

Solnce55 [7]3 years ago

7 0

1. Irrational
2. Additive inverse
3. Like terms
4. Absolute value
5. Inductive reasoning

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Solve for x 8x^2-7x-18=0

Arisa [49]

$8x^2-7x-18=0\\\\ 8x^2-16x+9x-18=0\\\\8x(x-2)+9(x-2)=0\\\\(x-2)(8x+9)=0\ \ \ \Leftrightarrow\ \ \ (x-2=0\ \ \ or\ \ \ 8x+9=0)\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=- \frac{9}{8}$

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4 years ago

What is the missing number? 45/9 = 12 - ?

shutvik [7]

Answer:

Step-by-step explanation:

45/9 = 5

12 - 7 = 5

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3 years ago

If a polygon has a vertex at (161, -329) and it is translated 168 units to the right, what are the coordinates of that vertex's

bearhunter [10]

Vertex of the polygon is (161, -329)

The new vertex is shifted 168 units to the right. A horizontal shift can be achieved be adding or subtracting the number from the x-coordinate. A change in the y coordinate brings the vertical shift. So in this case the x-component will change only and y component will be the same.

A shift towards right means, the value of x component is increase as x gets larger as we move towards right on the graph. So moving 168 units to the right, we will get the following vertex (329 , -329)

Thus, the new vertex of the polygon will be at the point (329, -329)

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3 years ago

Find the length of the arc. A. 15π mi B. 5400π mi C. 135π mi D. 125π16 mi

weqwewe [10]

Answer:

A. 15π mi

Step-by-step explanation:

First find the circumference

C = 2*pi*r

C = 2 * pi*18

C = 36pi

The arc is 150 degrees

The fraction of the circle is

150/360 = 5/12

Multiply this by the circumference

5/12 * 36 pi

15 pi

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3 years ago

Question 1 (33 points)

myrzilka [38]

Answer:

lol idk

Step-by-step explanation:

look it up

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3 years ago