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KATRIN_1 [288]
3 years ago
10

Phosphorus crystallizes in several different forms, one of which is a simple cube with an edge length of 238 pm. What is the den

sity of phosphorus in the simple cubic crystal form?
Chemistry
1 answer:
algol133 years ago
6 0

<u>Answer:</u> The density of phosphorus is 3.81g/cm^3

<u>Explanation:</u>

To calculate the density of phosphorus, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell = 1  (CCP)

M = atomic mass of phosphorus = 31 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = 238pm=238\times 10^{-10}cm    (Conversion factor:  1cm=10^{10}pm  )

Putting values in above equation, we get:

\rho=\frac{1\times 31}{6.022\times 10^{23}\times (238\times 10^{-10})^3}\\\\\rho=3.81g/cm^3

Hence, the density of phosphorus is 3.81g/cm^3

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<u>Explanation:</u>

Transmutation is defined as the process where one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of Californium-249 nucleus with Carbon-12 nucleus follows:

_{98}^{249}\textrm{Cf}+_6^{12}\textrm{C}\rightarrow _{Z}^{A}\textrm{X}+4_0^1\textrm{n}

In a nuclear reaction, the total mass and total atomic number remains the same.

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

249 + 12 = A + 4

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<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

98 + 6 = Z + 0

Z = 104

Hence, the isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

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Explanation:

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<u>Explanation</u>:

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