Which element forms a chloride of the type XCl2
1 answer:
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Answer:
0.267 mol
Explanation:
The <em>unbalanced equation</em> for the reaction that takes place is:
- C₈H₁₈ + O₂ → H₂O + CO₂
Once we balance it we're left with:
- 2C₈H₁₈ + 25O₂ → 18H₂O + 16CO₂
Using the <em>stoichiometric ratio </em>of water and octane from the balanced reaction, we can <u>convert mol of water into mol of octane</u>:
- 2.40 mol H₂O *
= 0.267 mol C₈H₁₈
Thus 0.267 moles of octane are needed to produce 2.40 mol of water.
Answer:
a) rate law = k[HgCl₂][C₂O₄²⁻]²
b) K = 8.67 * 10⁻⁵M⁻²s⁻¹
c) rate = 2.55 * 10⁻⁵Ms⁻¹
Explanation:
a) From the given data, rate law is given as: rate = k[HgCl₂]ᵃ[C₂O₄²⁻]ᵇ
Note: Further calculations and explanations are found in the attachment below
