Most of the mass of an atom is in the Nucleus.
Answer : The energy removed must be, 29.4 kJ
Explanation :
The process involved in this problem are :
The expression used will be:
where,
= heat released for the reaction = ?
m = mass of benzene = 94.4 g
= specific heat of solid benzene =
= specific heat of liquid benzene =
= enthalpy change for fusion =
Now put all the given values in the above expression, we get:
Negative sign indicates that the heat is removed from the system.
Therefore, the energy removed must be, 29.4 kJ
In the electrolysis of molten BaI₂, the product forms at the cathode Barium metal (Ba).
First ionic bonds in this salt are separated because of heat:
BaI₂(aq) → (aq) + I⁻(aq).
Reaction of reduction at cathode(-):
(aq) + 2e⁻ → 2Ba(s)
turns into Ba metal.
Reaction of oxidation at anode(+):
2I⁻(aq) → I₂(g) + 2e⁻.
So I⁻ turns into I₂(g)
The anode is positive and the cathode is negative.
In chemistry, the type of process in which decomposition of a chemical substance occurs due to the flow of electricity through the substance is generally known as the electrolysis process. Usually, the electrolysis process becomes in an arrangement in which one electrode of the cathode and one electrode of the anode are present.
In chemistry and production, electrolysis is a technique that makes use of direct electric present-day (DC) to power an otherwise non-spontaneous chemical response.
Electrolysis is commercially crucial as a degree inside the separation of factors from clearly going on sources including ores the usage of an electrolytic cell.
To learn more about the electrolysis please click on the link : brainly.com/question/24063038
#SPJ4
Answer:
Explanation:
The reaction produces two water molecules, so the mole ratio between oxygen and water is 1:2, but the mole ratio between water and hydrogen is 2:2.
Answer:
Explanation:
The solution of known concentration is expressed as molarity. Molarity is the mole fraction of solute (i.e. the dissolved substance) per liter of the solution, Molarity is also commonly called molar concentration.
Mathematically;
To copy and complete the road map from the given question, we have the following array:
Volume A (L)
↓
d. multiplied by the molarity of A
↓
moles A
↓
b. multiplied by the moles of B / moles of A
↓
moles B
↓
c. divided by the molarity of B
↓
volume B (L)