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QveST [7]
3 years ago
10

A method currently used by doctors to screen patients for a certain type of cancer fails to detect cancer in 15% of the patients

who actually have the disease. A new method has been developed that researchers hope will be able to detect cancer more accurately. A random sample of 80 patients known to this type of cancer is screened using the new method and the method failed to detect the cancer in 8 patients. At the 5% level of significance, can the researchers conclude that the new method is better than the one currently in use? (Can they conclude that the new method fails to detect cancer in less than 15% of the patients who actually have the disease?)
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

A technique presently used through docs to display screen ladies for breast most cancers fails to observe most cancers in 15% of the girls who without a doubt have the disease. A random pattern of eighty girls acknowledged to have breast most cancers are to be screened the use of a new technique that researchers suppose will be capable to realize most cancers greater accurately. At the 0.05 stage of significance, the researchers will be capable to conclude that the new approach is higher than the present day one if the fantastic.

Answer::: greater than 1.645

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Factor the trinomial 2x^2+15x+7
Mashutka [201]

Answer:

(2x+1)(x+7)

Step-by-step explanation:

2x2+15x+7

For a polynomial of the form ax2+bx+c

, rewrite the middle term as a sum of two terms whose product is a⋅c=2⋅7=14 and whose sum is b=15

.

Tap for more steps...

2x2+x+14x+7

Factor out the greatest common factor from each group.

Tap for more steps...

x(2x+1)+7(2x+1)

Factor the polynomial by factoring out the greatest common factor, 2x+1

.

(2x+1)(x+7)

3 0
2 years ago
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
Use ABC to find the value of cos a. 24/7 7/24 7/25 24/25
ExtremeBDS [4]

Answer:

\frac{24}{25}

Step-by-step explanation:

using the cosine ratio;

\cos(\theta)= \frac{adjacent}{hypotenuse}

From the question, the side of the right angle triangle that is adjacent to the measured <a,(i.e BAC) is AC=24 and the hypotenuse is AB=25

This implies that,

cos(a)= \frac{24}{25}

6 0
3 years ago
Is 1/5 bigger or smaller than 1/6
MAXImum [283]
You can tell if you make the denominators the same easiest one is 30 for 6 and 5
1/5=6/30
1/6=5/30

now you can see which is bigger
4 0
3 years ago
7. During a sale, the price of a pair of running shoes was marked down from $89.95 to $75.00. What was the
shutvik [7]

Answer:

16.6%

Step-by-step explanation:

(75/89.95)*100=83.37....

100-83.37...=16.62...

=16.6%

7 0
2 years ago
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