Answer:
False
Explanation:
This is not true at all. This can be done with a wide variety of resources in the modern world. There is the CPLEX (IBM ILOG CPLEX Optimization Studio) software, which was developed by Robert E. Bixby in 1988, it passed to several other companies and it was later sold to IBM in January 2009. Today it's one of the world's most effective programs when it comes to automated linear programming solutions.
A closed network<span> is a network confined to sites on internal web servers and only available to individuals within an organization.</span>
Answer:
The rise of digital media has caused newspaper subscriptions to decline significantly because people are finding their news online.
It is A
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int minn=INT_MAX;
int maxx=INT_MIN;
int n1,n2,n3,n4,n5;
cout<<"enter five Numbers:";
//read 5 Numbers
cin>>n1>>n2>>n3>>n4>>n5;
// find maximum
if(n1>maxx)
maxx=n1;
if(n2>maxx)
maxx=n2;
if(n3>maxx)
maxx=n3;
if(n4>maxx)
maxx=n4;
if(n5>maxx)
maxx=n5;
// find minimum
if(n1<minn)
minn=n1;
if(n2<minn)
minn=n2;
if(n3<minn)
minn=n3;
if(n4<minn)
minn=n4;
if(n5<minn)
minn=n5;
// print maximum and minimum
cout<<"maximum of five numbers is: "<<maxx<<endl;
cout<<"minimum of five numbers is: "<<minn<<endl;
return 0;
}
Explanation:
Declare two variables "minn" & "maxx" and initialize them with INT_MAX and INT_MIN respectively.Then read the five number from user and compare it with "minn" & "maxx" ,if input is greater than "maxx" then update "maxx" or if input is less than "minn" then update the "minn". After all the inputs, "minn" will have smallest and "maxx" will have largest value.
enter five Numbers:5 78 43 55 12
maximum of five numbers is: 78
minimum of five numbers is: 5
Answer:
Written in Python
import math
principal = 8000
rate = 0.025
for i in range(1, 11):
amount = principal + principal * rate
principal = amount
print("Year "+str(i)+": "+str(round(amount,2)))
Explanation:
This line imports math library
import math
This line initializes principal amount to 8000
principal = 8000
This line initializes rate to 0.025
rate = 0.025
The following is an iteration from year 1 to 10
for i in range(1, 11):
This calculates the amount at the end of the year
amount = principal + principal * rate
This calculates the amount at the beginning of the next year
principal = amount
This prints the calculated amount
print("Year "+str(i)+": "+str(round(amount,2)))
