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2 answers:
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Answer:
2048 blocks
Explanation:
From the information given:
The memory size of a computer with fully associative cache = 2¹⁶ bytes
The no. of blocks in a single cache = 64
In which each block size = 32 bytes
The no of blocks in the main memory = memory size ÷ block size
The no of blocks in the main memory = 2¹⁶ ÷ 32
The no of blocks in the main memory = 2¹⁶ ÷ 2⁵
The no of blocks in the main memory =
The no of blocks in the main memory = 2¹¹
The no of blocks in the main memory = 2048 blocks
Answer:
Hey there!
Explanation:
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