if the length of LMNP was greater than the width
66%, then 2/3, and lastly 0.67. 2/3 is repeating so it is more then 66% but less than 0.67
Answer:
I guess D is the answer for the question
Answer:
about 8.2 cm
Step-by-step explanation:
The key is to realize that the volume never changes.
The formula for the volume of a sphere is (4/3)*pi*radius^3
22/7 is being substituted in place of pi in this problem
The volume of one of the small spheres is
(4/3)*(22/7)*2^3 is about 33.524 cm^3
64 of those spheres would have a volume of 33.524*64, or about 2145 cm^3
Now, the problem is to find a sphere with a volume of 2145 cm^3
Volume = (4/3)*(22/7)*radius^3
plug in and solve
2145 = 4.1905*r^3
r^3=511.87
r is about equal to 8.2 centimeters
Answer:
width = 1.8 in
length = 3.6 in
height =
Step-by-step explanation:
A designer is making a rectangular prism box with maximum volume, with the sum of its length, width, and height 8 in
Let l , w and h are the length , width and height

Plug it in the first equation

volume the box is length times width times height

To get maximum volume we take derivatived

set the derivative =0 and solve for w

width = 1.8 in
length = 2w= 3.6 in
height =