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faust18 [17]
3 years ago
10

Based on table j, which metal is more active than tin but less active than zinc

Chemistry
2 answers:
elena55 [62]3 years ago
8 0

Answer:Cr

Explanation: Could be Cr Fe Co or Ni

bonufazy [111]3 years ago
3 0

Answer:

Chromium, Iron, Cadmium, Cobalt, Nickel.

<em>Cr> Fe> Cd> Co> Ni</em>

Explanation:

Assuming table J is based on the reactivity series, metals which are more active than tin but less active than zinc are listed in the above range. The reactivity series is useful for single displacement product determinations where metals displace each other in reaction.

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Not guarenteed the answer, but as the temperature increases, the molecules in the gas move faster, impacting the gas's containor more frequently and exerting a greater force, according to Gay-Lussac's Law. I hope this helps you.
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This science of classifying organisms is called?
Verdich [7]

The classifying of organisms is called "Taxonomy" or the second option. Taxonomy mainly takes place with organisms although it could be used to classify anything. Taxonomy consists of a graph with eight categories all used to classify a living organism.

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Based on the equation, how many grams of Br2 are required to react completely with 29.2 grams of AlCl3?
goblinko [34]

Answer:

answer is 34.996 or 35 grams

Explanation:

Br2 + AlCl3

mass 34.996 29.2

RFM 160 133.5

moles 0.2187 0.2187

3 0
3 years ago
A nonvolatile organic compound Z was used to make up a solution. Solution A contains 6.00 g of Zdissolved in 100 g of waterand h
olya-2409 [2.1K]

Answer:

Molar mass of Z in solution A is 148.2 g/mol.

Explanation:

To solve this, we need to use colligative property about vapor pressure.

In any ideal solution, the vapor pressure of solution is lower than vapor pressure of pure solvent. Formula is:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

At the normal boiling point of water (100°C), vapor pressure is 760 mmHg.

Let's replace in the formula, to find out Xm (mole fraction of solute)

760 mmHg - 754.5 mmHg = 760 mmHg . Xm

(760 mmHg - 754.5 mmHg) / 760 mmHg = Xm

Xm → 0.00724

Mole fraction of solute = moles of solute /total moles (st + sv)

In this case, our mole fraction will be

(6 g / MM) / ( (6 g/ MM + 100 g / 18g/mol) = 0.00724

Our unknown is MM (molar mass of Z). We solve the equation:

6 g / MM = 0.00724 . ((6 g/ MM + 100 g / 18g/mol))

6 g / MM =  0.04344 g /MM + 0.0402 g/mol

6 g/MM - 0.04344 g /MM = 0.0402 g/mol

5.95656 /MM = 0.0402 g/mol

5.95656 / 0.0402 g/mol = MM → 148.2 g/mol

4 0
3 years ago
Complete ionic,net and spectator ions for the following
yawa3891 [41]

Answer:

Explanation:

1) ZnBr₂ (aq) + AgNO₃ (aq)

Chemical equation:

 ZnBr₂ (aq) + AgNO₃ (aq)  →Zn(NO₃)₂(aq) + AgBr(s)

Balanced chemical equation:

ZnBr₂ (aq) + 2AgNO₃ (aq)  →Zn(NO₃)₂(aq) + 2AgBr(s)

Ionic equation:

Zn²⁺(aq) + Br₂²⁻ (aq) + 2Ag⁺ (aq)+ 2NO⁻₃ (aq)  → Zn²⁺(aq) +(NO₃)₂²⁻(aq) + 2AgBr(s)

Net ionic equation:

Br₂²⁻ (aq) + 2Ag⁺ (aq)   →    2AgBr(s)

The Zn²⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The AgBr can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

2) Ca(OH)₂ (aq) + Na₂SO₄ (aq)

Chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq)  →   CaSO₄(s) + NaOH(aq)

Balanced chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq)  →   CaSO₄(s) + 2NaOH(aq)

Ionic equation:

Ca²⁺(aq)  + OH₂²⁻  (aq) + 2Na⁺(aq) + SO₄²⁻ (aq)  →   CaSO₄(s) + 2Na⁺(aq) + 2OH⁻ (aq)

Net ionic equation:

Ca²⁺(aq)   + SO₄²⁻ (aq)  →   CaSO₄(s)

The OH⁻ ((aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The CaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

3) Al(NO₃)₃ (aq) + Na₃PO₄ (aq)

Chemical equation:

 Al(NO₃)₃ (aq) + Na₃PO₄ (aq)   → Al(PO₄)(s) + NaNO₃ (aq)

Balanced chemical equation:

Al(NO₃)₃ (aq) + Na₃PO₄ (aq)   → Al(PO₄)(s) + 3NaNO₃ (aq)

Ionic equation:

Al³⁺(aq) + 3NO⁻₃ (aq) + 3Na⁺(aq) + PO₄³⁻ (aq)   → Al(PO₄)(s) + 3Na⁺(aq) + NO⁻₃ (aq)

Net ionic equation:

Al³⁺(aq) + PO₄³⁻ (aq)   → Al(PO₄)(s)

The Na⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The  Al(PO₄) can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

4) FeSO₄ (aq) + Ba(OH)₂ (aq)

Chemical equation:

FeSO₄ (aq) + Ba(OH)₂ (aq)  → BaSO₄(s) + Fe(OH)₂(aq)

The equation is already balanced.

Ionic equation:

Fe²⁺(aq)  + SO₄²⁻ (aq) + Ba²⁺(aq)  + 2OH⁻ (aq)  → BaSO₄(s) + Fe²⁺(aq)  + 2OH⁻(aq)

Net ionic equation:

SO₄²⁻ (aq) + Ba²⁺(aq) → BaSO₄(s)

The Fe²⁺ (aq) and OH⁻ (aq) are spectator ions that's why these are not written in net ionic equation. The  BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

8 0
3 years ago
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