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salantis [7]
3 years ago
6

A hydrated form of copper sulfate (CuSO4·x H2O) is heated to drive off all the water. If we start with 8.79 g of hydrated salt a

nd have 6.57 g of anhydrous CuSO4 after heating, find the number of water molecules associated with each CuSO4 formula unit.
Chemistry
1 answer:
exis [7]3 years ago
4 0

Answer:

3 water molecules

Explanation:

The molar ratio between CuSO₄ and H₂O needs to be calculated.

The mass of water that was removed by heating is calculated, then converted to moles. The molecular weight of water is 18.02g/mol.

(8.97 g - 6.57 g) = 2.22 g H₂O

(2.22 g)/(18.02g/mol) = 0.1232 mol H₂O

The moles of anhydrous copper sulfate are calculated. The molecular weight is 159.609 g/mol

(6.57 g)/(159.609 g/mol) = 0.04116 mol CuSO₄

Now the molar ratio between CuSO₄ and H₂O can be calculated:

0.1232 mol H₂O ÷ 0.04116 mol CuSO₄ = 3 H₂O / CuSO₄

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Producer gas is a fuel formed by passing air over red-hot coke (amorphous carbon). What mass of a producer gas that consists of
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Producer gas is a fuel that is produced by burning biomass with an air deficit passed over red-hot coke (amorphous carbon). This gas is nothing but a mixture of gases such as hydrogen (H), carbon monoxide (CO), carbon dioxide (CO₂) and nitrogen (N₂).

The equation of producer gas is as follows -

                            CO₂ + 2N₂ (air) → CO + 2N₂

                            ΔH = -27.06 kcal

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1 Ton = 1000 kg

Mass of coke needed to form producer gas = 1.75 tons = 1750 kg

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Carbon monoxide (CO) = 25%  

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1000 kg of coke produces = 2048.73 kg of producer gas

∴ 1 kg of coke produces = 2048.73 ÷ 1000 kg of producer gas

∴ 1750 kg of coke produces = 2048.73 × 1750 / 1000 = 3585.28 kg of producer gas.

Percentage yield = 87%

                             = 3585.28 × 87/100

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