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salantis [7]
3 years ago
6

A hydrated form of copper sulfate (CuSO4·x H2O) is heated to drive off all the water. If we start with 8.79 g of hydrated salt a

nd have 6.57 g of anhydrous CuSO4 after heating, find the number of water molecules associated with each CuSO4 formula unit.
Chemistry
1 answer:
exis [7]3 years ago
4 0

Answer:

3 water molecules

Explanation:

The molar ratio between CuSO₄ and H₂O needs to be calculated.

The mass of water that was removed by heating is calculated, then converted to moles. The molecular weight of water is 18.02g/mol.

(8.97 g - 6.57 g) = 2.22 g H₂O

(2.22 g)/(18.02g/mol) = 0.1232 mol H₂O

The moles of anhydrous copper sulfate are calculated. The molecular weight is 159.609 g/mol

(6.57 g)/(159.609 g/mol) = 0.04116 mol CuSO₄

Now the molar ratio between CuSO₄ and H₂O can be calculated:

0.1232 mol H₂O ÷ 0.04116 mol CuSO₄ = 3 H₂O / CuSO₄

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Answer:

5)HOCH2CH2OH

Explanation:

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3 0
3 years ago
You make an experiment to determine the percent mass of carbon in sugar. You find out that there is 46.63g of carbon in 75.00g o
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Taking into account the definition of percentage composition, the percent composition of carbon in this sample is 62.17%.

<h3>Percentage composition</h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

Then, the percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

percentageby mass= \frac{mass of solute}{mass of solution}x100

<h3>This case</h3>

In this case, you know:

  • mass of solute= 46.63 g
  • mass of solution= 75 g

Replacing:

percentageby mass= \frac{46.63 g}{75 g}x100

Solving:

<u><em>percentage by mass= 62.17 %</em></u>

Finally, the percent composition of carbon in this sample is 62.17%.

Learn more about percent composition:

<u>brainly.com/question/24201923?referrer=searchResults</u>

<u>brainly.com/question/9779410?referrer=searchResults</u>

<u>brainly.com/question/17030163?referrer=searchResults</u>

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