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irga5000 [103]
3 years ago
13

A system does 125 J of work and cools down by releasing 438 J of heat. The change in internal energy is ____________ J.

Chemistry
1 answer:
Jet001 [13]3 years ago
8 0

Given that,

Work done by the system = 125 J

Energy released when it cools down = 438 J

To find,

The change in internal energy.

Solution,

As heat is released by the system, Q = -438 J

Work done by the system, W = -125 J

Using the first law of thermodynamics. The change in internal energy is given by :

\Delta U=Q-W\\\\=-438-125\\\\=-563\ J

So, the change in internal energy is 563 J.

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