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bazaltina [42]
3 years ago
7

X^3 [3-2x) 5(23-3)5 (8) |2|

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0
I think the answer is <span>−<span>16000<span>x^4</span></span></span>+<span>24000<span>x^<span>3</span></span></span>
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What is the slope of the equation: x = -2
Harrizon [31]

Answer:

undefined

Step-by-step explanation

it is a vertical line and has no defined slope

5 0
3 years ago
2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
Stells [14]

y'=(t+y)^2-1

Substitute u=t+y, so that u'=y', and

u'=u^2-1

which is separable as

\dfrac{u'}{u^2-1}=1

Integrate both sides with respect to t. For the integral on the left, first split into partial fractions:

\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

\dfrac12(\ln|u-1|-\ln|u+1|)=t+C

Solve for u:

\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C

\ln\left|1-\dfrac2{u+1}\right|=2t+C

1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}

\dfrac2{u+1}=1-Ce^{2t}

\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}

u=\dfrac2{1-Ce^{2t}}-1

Replace u and solve for y:

t+y=\dfrac2{1-Ce^{2t}}-1

y=\dfrac2{1-Ce^{2t}}-1-t

Now use the given initial condition to solve for C:

y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

so that the particular solution is

y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}

3 0
3 years ago
How does someone find the measurement of a triangle's side by the given angles inside the triangle?
romanna [79]
You use the formula given and it usually involves dividing
8 0
3 years ago
If x does not equal 16 then 2x+10 does not equal 42​
Lady bird [3.3K]

Answer:

The answer is

True

5 0
3 years ago
Read 2 more answers
Can someone help me solve this
Law Incorporation [45]

Answer: 28

Step-by-step explanation: 2x14=28

7x4=28

Both are factors of 28

4 0
3 years ago
Read 2 more answers
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