Answer:
The question is incomplete.The full question with options is rewritten below:
"While investigating an email issue, a support technician discovers no users can access their email accounts on the company’s email server connected to the private LAN. Pinging the email server from several workstations on the LAN results in 0% packet loss.
Which of the following is the next step the technician should take in troubleshooting this issue?
A. Contact the ISP, inform the provider of the issue, and ask the provider to check the server.
B. Verify the server has a valid assigned IP address on the LAN subnet.
C. Escalate the problem to a server administrator to check for issues with the server.
D. Check the workstations on the LAN for APIPA configuration."
The answer is option (C): <em>Escalate the problem to a server administrator to check for issues with the server</em>
Explanation:
Being a Support Technician, you may not be able to determine the main issue with the mail server but may need to escalate further to the next category of individual that will confirm the issue with the mail server, in this case the server administrator as he may have higher access into the server at the back end or may directly liaise with the Private ISP.
Answer:
This code will print: 4
Explanation:
Following is the step-by-step explanation for the given code:
- Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:
double[] myList = {1, 5, 5, 5, 5, 1};
- Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).
double max = myList[0];
- A variable indexOfMax having datatype int will be initiated as 0.
int indexOfMax = 0;
- Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.
for (int i = 1; i < myList.length; i++)
{ if (myList[i] >= max)
{ max = myList[i];
- Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).
indexOfMax = i; }}
- At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.
System.out.println(indexOfMax);
i hope it will help you!
Answer:
Infrastructure as a service(Iaas)
Explanation:
Infrastructure as a service(Iaas) is used to provide hardware,storage,servers and datacenter space or network components
