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FromTheMoon [43]
3 years ago
11

HELP! I NEED THIS ANSWERED ASAP!!!

Chemistry
1 answer:
stealth61 [152]3 years ago
8 0

Answer:

The rate of reaction will maintain constant

Explanation:

Rate of reaction is proportionate to rate constant x [A] ^2 x [B]. This means that the order of reaction with respect to C is 0 as it does not affect the rate of reaction as seen in the rate equation.

Essentially, order of reaction with respect to C is [C] ^0

Hence if [C] triples and becomes [3C]^0, the result will still be 1 as anything to the power of 0 is 1.

Therefore, the answer is that the rate of reaction will remain constant.

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Th e enzyme-catalyzed conversion of a substrate at 25°C has a Michaelis constant of 0.045 mol dm−3. Th e rate of the reaction is
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v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}

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v = rate of formation of products =

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V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s

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