Question

Write a balanced chemical equation for the standard formation reaction of gaseous hydrogen fluoride hf

Answer 1

Answer:  A balanced chemical equation for the standard formation reaction is  $\frac{1}{2}H_{2}(g)+\frac{1}{2}F_{2}(g)\rightarrow HF(g)$

Explanation:

A balanced chemical equation is the equation in which number of reactants equals the number number of products.

The balanced chemical equation for the formation of gaseous hydrogen fluoride is as follows.

        $\frac{1}{2}H_{2}(g)+\frac{1}{2}F_{2}(g)\rightarrow HF(g)$

Here, in this equation half molecule of $H_{2}$ reacts with half molecule of $F_{2}$ to give 1 molecule of HF.

Thus, the sum of number of reactant molecules equals the number of product molecules. Therefore, it is a balanced equation.

Therefore, the equation is  $\frac{1}{2}H_{2}(g)+\frac{1}{2}F_{2}(g)\rightarrow HF(g)$

Answer 2

The  standard  state formation reaction  is  a  chemical  reaction  in  which one  moles  of  substance  in  its  standard state  is formed from  its constituent  element in  their  standard  state.All  the  substance must  be  in  their  most stable  state  at  100kpa  and  25  degrees  celsius.
therefore  for  HF is
1/2H2 +1/2F2 =HF