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Bumek [7]
3 years ago
14

Jarvis checked his odometer reading when filling his tank, and then checked it several days later when he filled his tank again.

His first reading was 65,290 miles and the second was 65,500 miles. It took eight gallons of gas to fill his tank. How many miles per gallon is he getting?
Chemistry
2 answers:
8_murik_8 [283]3 years ago
4 0

Answer: 26.25 miles per gallon

Explanation: first odometer reading = 65290

Second odometer reading = 65500

Difference in odometer reading = second reading - first reading

= 65500 - 65290 = 210 miles.

If it took 8 gallons to fill his tank, it means

8 gallons will get him 210 miles, therefore 1 gallon will get 210 miles/8gallons = 26.25miles/gallon. Hence he is getting 26.25miles/gallon.

Alinara [238K]3 years ago
3 0

Answer:

26.25 miles/gallon.

Explanation:

Initial distance, d1 = 65290 miles.

Final distance, d2 = 65500

Distance travelled = d2 - d1

= 65500 - 65290

= 210 miles

Volume of Gasoline used for the distance = 8 gallons.

= Distance/volume

= 210/8

= 26.25 miles/gallon.

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Dana is trying to determine if an unknown sample is a pure substance or not. The sample has a cloudy white color, and it seems e
Firdavs [7]

Answer:

Dana filtered the sample and larger granules of the sample were left behind.

Explanation:

If a substance is pure, it will have a uniform composition throughout. It will not separate into particles of various sizes.

One of the characteristics of pure substances is that they are homogeneous. A mixture is definitely made up of particles of various sizes.

Since the particles was filtered and larger granules were left behind, the sample has been separated by a physical method (filtration). Only a mixture can be separated by physical methods. It is not a pure substance.

5 0
3 years ago
B. Which of the following compounds can
Tamiku [17]

Answer:

The correct answer is:

d. Na2S, NaF

4 0
3 years ago
Read 2 more answers
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
The radioactivity due to carbon-14 measured in a piece of a wooden casket from an ancient burial site was found to produce 20 co
bekas [8.4K]

Answer:

17202.6 years

Explanation:

Activity of the living sample (Ao) = 160 counts per minute

Activity of the wood sample (A) = 20 counts per minute

Half life of carbon-14 = 5730 years

t= age of the artifact

From;

0.693/t1/2= 2.303/t log Ao/A

Then;

0.693/ 5730= 2.303/t log Ao/A

Substituting values;

0.693/5730= 2.303/t log (160/20)

Then we obtain;

1.209×10^-4 = 2.0798/t

t= 2.0798/1.209×10^-4

Thus;

t= 17202.6 years

Therefore the artifact is 17202.6 years old.

3 0
3 years ago
What is the value for ∆Soreaction for the following reaction, given the standard entropy values?
Soloha48 [4]
To get the ∆S of the reaction, we simply have to add the ∆S of the reactants and the ∆S of the products. Then, we get the difference between the ∆S of the products and the ∆S of the products. If the <span>∆S is negative, then the reaction spontaneous. If the otherwise, the reaction is not spontaneous.</span>
8 0
3 years ago
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