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-BARSIC- [3]
3 years ago
14

What is the wavelength of an electromagnetic wave that travels at 3 × 108 m/s and has a frequency of 60 MHz? (1 MHz = 1,000,000

Hz)
Chemistry
1 answer:
VikaD [51]3 years ago
8 0

Answer: 5m

Explanation:

Given that:

Wavelength (λ)= ?

Frequency of wave (F) = 60MHz

[If 1 MHz = 1,000,000 Hz

60MHz = 60 x 1,000,000 = 6 x 10^7Hz]

Speed of wave (V) = 3 x 10^8 m/s

The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ.

So, apply the formula V = F λ

Make λ the subject formula

λ = V/ F

λ = 3 x 10^8 m/s / 6 x 10^7Hz

λ = 5m

Thus, the wavelength of an electromagnetic wave is 5 metres.

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Explanation:

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A 6.35 l sample of carbon monoxide is collected at 55.0◦c and 0.892 atm. What volume will the gas occupy at 1.05 atm and 59.0◦c?
Sonja [21]

Answer : The final volume of gas will be, 5.46 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.892 atm

P_2 = final pressure of gas = 1.05 atm

V_1 = initial volume of gas = 6.35 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 55.0^oC=273+55.0=328K

T_2 = final temperature of gas = 59.0^oC=273+59.0=332K

Now put all the given values in the above equation, we get:

\frac{0.892atm\times 6.35L}{328K}=\frac{1.05atm\times V_2}{332K}

V_2=5.46L

Thus, the final volume of gas will be, 5.46 L

7 0
3 years ago
A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

    = (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

     = (-75000 J) - ( -13071 J)

     =  -75000 J + 13071 J

     = -61929 J

Total energy change, ΔE = -61.929 kJ

3 0
4 years ago
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