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3 years ago

The aldol reaction is catalyzed by acid as well as base. What is the reactive nucleophile in the acid-catalyzed aldol reaction

Chemistry

1 answer:

svp [43]3 years ago

4 0

Answer:

The reactive nucleophile is Ketone.

Explanation:

In organic chemistry, The process of acid - catalyzed aldol condensation starts from when ketone (or any aldehyde) is converted to an -enol, after which it attacks another ketone/aldehyde that has already been activated by parbonyl oxygen protonation.

The process of this is that first of all the ketone undergoes tautomerization to form -enol. Thereafter, the other carbonyl will undergo protonation which makes the carbon activated towards attack. Now, the nucleophilic enol will be added to the carbonyl in a [1,2]-addition reaction and we will now use deprotonation to obtain the neutral Aldol product.

Now, since only the ketone can produce an -enol, thus it is the nucleophile as aldehydes are better electrophiles

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As a form of energy, light has specific properties such as color and brightness. Some properties can only be seen with special t

Sergeu [11.5K]

Answer:

D. As white light passes through a prism , it bends and separates into different colors

Explanation:

When light enters a prism, it experiences a phenomenon called 'refraction'.

Refraction occurs when light crosses the interface between two mediums with different optical density; when this happens, the light bends and also changes speed.

The angle at which the ray of light is refracted into the second medium depends on the optical density of the two mediums, but also on the wavelength of the light.

In particular, longer wavelengths (red color) are refracted the least, while shorter wavelengths (violet color) are refracted the most.

As a result, when white light (consisting of all the colors of visible light) enters into a prism, they different wavelengths are separated: therefore, white light separates into different colors.

So, the correct answer is

D. As white light passes through a prism , it bends and separates into different colors

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4 years ago

____________ is the process used to separate the solvent from a solution

bixtya [17]

Distillation :)
:) :) :) :) :) :)

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2 years ago

How many molecules are in 0.500 mole of N2O5?

Oksi-84 [34.3K]

Answer:

3,011.10e23.

Explanation:

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3 years ago

A student was conducting an experiment designed to study the law of conservation of mass. The student measured the mass of all t

never [62]

562 grams because mass can not be created or destroyed

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3 years ago

Be sure to answer all parts. A 0.365−mol sample of HX is dissolved in enough H2O to form 835.0 mL of solution. If the pH of the

Marta_Voda [28]

Answer:

The Ka is 9.11 *10^-8

Explanation:

Step 1: Data given

Moles of HX = 0.365

Volume of the solution = 835.0 mL = 0.835 L

pH of the solution = 3.70

Step 2: Calculate molarity of HX

Molarity HX = moles HX / volume solution

Molarity HX = 0.365 mol / 0.835 L

Molarity HX = 0.437 M

Step 3: ICE-chart

[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4

Initial concentration of HX = 0.437 M

Initial concentration of X- and H3O+ = 0M

Since the mole ratio is 1:1; there will react x M

The concentration at the equilibrium is:

[HX] = (0.437 - x)M

[X-] = x M

[H3O+] = 1.995*10^-4 M

Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4

[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M

[X-] = x = 1.995*10^-4 M

Step 4: Calculate Ka

Ka = [X-]*[H3O+] / [HX]

Ka = ((1.995*10^-4)²)/ 0.437

Ka = 9.11 *10^-8

The Ka is 9.11 *10^-8

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3 years ago