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alexandr1967 [171]
3 years ago
5

A sample of hydrogen occupies a volume of 351 mL at a temperature of 20 degrees Celsius. What is the new volume if the temperatu

re increases to 38 degrees Celsius? (Do not forget to convert to Kelvin!)
Chemistry
1 answer:
xeze [42]3 years ago
6 0
Volume of Hydrogen V1 = 351mL 
Temperature T1 = 20 = 20 + 273 = 293 K 
Temperature T2 = 38 = 38 + 273 = 311 K 
We have V1 x T2 = V2 x T1 
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56 
Volume at 38 C = 373 ml
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Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume
IgorC [24]

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm  (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K=

n=\frac{PV}{RT}

n=\frac{1atm\times 3.16L}{0.0820 L atm/K mol\times 273K}=0.141moles

CH_4+4Cl_2\rightarrow 4HCl+CCl_4

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces = \frac{1}{4}\times 0.141=0.0352 moles of carbon tetrachloride

volume of carbon tetrachloride =moles\times {\text {Molar volume}}=0.0352mol\times 22.4L/mol=0.788L

Thus volume of carbon tetrachloride that would be produced is 0.788 L

8 0
3 years ago
Balance the following chemical equations
nexus9112 [7]

Explanation:

  1. 2Na + I₂ → 2NaI
  2. 2KClO₃ → 2KCl + 3O₂
  3. K₃PO₄ + 3HCl → 3KCl + H₃PO₄

6 0
2 years ago
In the chemical reaction:Br2(g) + Cl2(g) ⇌ 2 BrCl(g) KP = 0.150If there is initially 0.500 atm of BrCl and nothing else in a con
klemol [59]

Answer:

The partial pressure of BrCl at equilibrium is 0.08 atm.

Explanation:

The equilibrium constant of the reaction is given by =K_p=0.150

Br_2(g) + Cl_2(g)\rightleftharpoons 2 BrCl(g)

initial

0       0         0.500 atm

At equilbrium

p      p       (0.500-2p)

The equilibrium constant's expression of the reaction is given by ;

 K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}

0.150=\frac{(0.500-2p)^2}{p\times p}

Solving for p:

p = 0.21 atm

The partial pressure of BrCl at equilibrium is:

(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]

7 0
3 years ago
BRAINLIEST, 5 STARS, AND THANKS!!!<br><br>tapos na po ako Dyan katapos kulang ma answer
mezya [45]

Answer:

before

1. Prepare a handy emergency supply kit

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3. Familiarize yourself with the exit routes

During

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Hope this will help you.

5 0
2 years ago
1.5g of magnesium ribbon is burnt in oxygen to produce 2.5g of magnesium oxide. How much oxygen is required in grams?
Furkat [3]

Answer:

2.5 grams

Explanation:

law of conservation of mass applies. the magnesium completely burns

4 0
3 years ago
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