According to the Journal of the American Medical Association (JAMA), hospitals that routinely staff with 1:8 nurse-to-patient ra
2 answers:
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Answer:
Step-by-step explanation:
Combine real terms and combine complex terms
1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i
= 5 + (2-5)i
= 5 + (-3)i
= 5 - 3i
3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i) = 2 -1 + 2i + 4 - 5i - 1 + 3i
{- is distributed to (1 - 2i) & - is distributed to (1- 3i)}
= 2 - 1 + 4 + 1 + 2i - 5i + 3i
= 6 +0i = 6
5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i
= 8
7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i {(a - b)² = a² - 2ab +b²}
= 9 -12i + 4i² + 3 + 2i
= 9 - 12i + 4*(-1) + 3 + 2i {i² = -1}
= 9 +3 - 4 - 12i +2i
= 8 - 10i
Answer:
see graph of y = 5x - 7
Step-by-step explanation:
If graphing is the task, you should rewrite the equation in a y = ax + b form. All straight lines can be described in this form, only the a and b determine which line it is.
Your equation 5x-y=7 has the 5x on the left side, so lets move it to the right. It will get a negative sign (this is the same as subtracting 5x like you did in your picture)
5x - y = 7
-y = 7 - 5x
Now we still have the -y which should be a +y. So we multiply left and right with -1 and get:
y = -7 + 5x
If we swap the -y and 5x (we can, because they are just an addition), we get:
y = 5x - 7
Now the equation is in its "normal" form. It's like the y = ax + b with a and b chosen as a=5 and b=-7.
The normal form is handy because you can immediately see the slope is 5 and the intersection with the y-axis is at y=-7.
