Answer:
7 is the greatest number of bags Jason can fill.
Step-by-step explanation:
Given: Jason has 14 raspberry scones and 35 blackberry scones.
Now, finding the maximum number of bags Jason can fill with equal number of raspberry scones and blackberry scones.
∴ we will be using Greatest common factor (GCF) for knowing the number of bags.

∴ 
7 is the greatest number of bags that Jason can fill with equal number of raspberry and blackberry scones.
Answer:
the answer is associative
Step-by-step explanation:
Answer:
4x / (2x^2+1)
Step-by-step explanation:
g(x)=ln(2x^2+1)
Using u substitution
u= 2x^2 +1
du = 4x dx
g'(x) = d/du ( g(u) du)
We know that the derivative of ln(u) = 1/u since this is always positive
= 1/ u* du
Substituting x back into the equation
g'(x) = 1/(2x^2+1) * 4x
= 4x / (2x^2+1)
Answer:
-2/3x+y=7
Step-by-step explanation:
standard is AxBy=C
so move the 2/3 over to get 7 by itself.