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emmasim [6.3K]
3 years ago
7

A rotating object makes 5/6 of a revolution in 7/10 second. Find the approximate speed in revolutions per second. Write your ans

wer as a decimal to the nearest hundreth.
Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

1.19 revolutions per second.

Step-by-step explanation:

Given:

A rotating object makes 5/6 of a revolution in 7/10 second.

To find:

Find the approximate speed in revolutions per second ?

Solution:

As here given that a rotating object makes 5/6 of a revolution in 7/10 second,

we will have to find that in one second how many revolution does this object make:

By unitary method:

In \frac{7}{10} second, a rotating object makes = \frac{5}{6}  revolution

In 1 second, a rotating object makes = \frac{5}{6}\div\frac{7}{10}

                                                            =\frac{5}{6}\times\frac{10}{7} = \frac{50}{42}=1.190\ revolution

Therefore, the approximate speed of object is 1.19 revolution per second.

We can also find by, speed = \frac{distance}{time}

                                            =\frac{5}{6} \div\frac{7}{10} \\=\frac{5}{6} \times\frac{10}{7} =\frac{50}{42} = 1.19

We can use any one to solve this type of question:

Finally, the approximate speed is 1.19 revolutions per second.

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3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
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