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emmasim [6.3K]
3 years ago
7

A rotating object makes 5/6 of a revolution in 7/10 second. Find the approximate speed in revolutions per second. Write your ans

wer as a decimal to the nearest hundreth.
Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

1.19 revolutions per second.

Step-by-step explanation:

Given:

A rotating object makes 5/6 of a revolution in 7/10 second.

To find:

Find the approximate speed in revolutions per second ?

Solution:

As here given that a rotating object makes 5/6 of a revolution in 7/10 second,

we will have to find that in one second how many revolution does this object make:

By unitary method:

In \frac{7}{10} second, a rotating object makes = \frac{5}{6}  revolution

In 1 second, a rotating object makes = \frac{5}{6}\div\frac{7}{10}

                                                            =\frac{5}{6}\times\frac{10}{7} = \frac{50}{42}=1.190\ revolution

Therefore, the approximate speed of object is 1.19 revolution per second.

We can also find by, speed = \frac{distance}{time}

                                            =\frac{5}{6} \div\frac{7}{10} \\=\frac{5}{6} \times\frac{10}{7} =\frac{50}{42} = 1.19

We can use any one to solve this type of question:

Finally, the approximate speed is 1.19 revolutions per second.

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Small scooters cost £80 and large scooters cost £130. A school buys few scooters for the playground for £1000. How many of the s
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Large scooters = 4

Step-by-step explanation:

Let S represents small scooter and L represents large scooter

The cost of a small scooter is £80

Mathematically,  the cost of S number of small scooters is

80S

The cost of a large scooter is £130

Mathematically,  the cost of L number of large scooters is

130L

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Mathematically,

80S + 130L = 1000

So we have 2 unknowns and only 1 equation. Therefore, we have use trial and error method .

Trial and Error Method:

80S + 130L = 1000

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Let’s suppose they bought 1 large scooter

S = (1000 - 130(1))/80

S = 10.875

Number of scooters cannot be in fraction so 1 doesn’t work

Let’s suppose they bought 2 large scooter s

S = (1000 - 130(2))/80

S = 9.25

Number of scooters cannot be in fraction so 2 doesn’t work

Let’s suppose they bought 3 large scooter s

S = (1000 - 130(3))/80

S = 7.625

Number of scooters cannot be in fraction so 3 doesn’t work

Let’s suppose they bought 4 large scooters

S = (1000 - 130(4))/80

S = 6

So that means they bought 6 small scooters and 4 large scooters.

Similarly, other combinations for scooters don’t work since they yield either fractional value or negative value which cannot be correct.

Therefore, the only possible combination of small and large scooters is

6 Small scooters

4 Large scooters

Verification:

80S + 130L = 1000

80(6) + 130(4) = 1000

480 + 520 = 1000

1000 = 1000 (satisfied)

8 0
4 years ago
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