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Scilla [17]
3 years ago
13

The most common element in the atmosphere are

Chemistry
1 answer:
Ivanshal [37]3 years ago
8 0
Nitrogen and oxygen are the most prevalent in the atmosphere.
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Calculate the number of atoms
erastova [34]

Explanation:

13 are the number of atoms

4 0
3 years ago
a solution was made by mixing sodium chloride () and water (). given that the mole fraction of water is 0.980 in the solution ob
Mnenie [13.5K]

The mass of sodium chloride used <u>was 1.17 grams</u><u>.</u>

The mole fraction can be calculated by way of dividing the number of moles of 1 factor of an answer via the full variety of moles of all the additives of an answer. it is mentioned that the sum of the mole fraction of all the components inside the solution has to be the same as one.

mass  of NaCl given =  64.9 g

mole  = mass/molar mass

          = 64.9 / 58.5

          =<u> 1.109</u>

a mole fraction of water =  0.980

mole fraction of NaCl = 1 - 0.980

                                   = <u>0.02</u>

1 mole of NaCl =  58.5

mass of NaCl  = 58.5 × 0.02

                       =<u> 1.17 gram</u>

Mole Fraction describes the range of molecules contained within one aspect divided through the whole range of molecules in a given combination. it's miles quite beneficial whilst two reactive-natured components are mixed collectively.

Learn more about mole fraction here:-brainly.com/question/29111190

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4 0
1 year ago
What is the proper name for Zn(CIO)2?
Sergio [31]

Answer:

ZINC CHLORATE

Explanation:

Zinc chloride is the name of chemical compounds with the formula ZnCl2 and its hydrates.

3 0
3 years ago
Read 2 more answers
A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens
skad [1K]

The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

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4 0
1 year ago
a 250.0 ml buffer solution is 0.250 M in acetic acid and. 250M in sodium acetate. what is the ph after addition of. 0050 mol of
maw [93]
Hello there.

<span>A 250.0 ml buffer solution is 0.250 M in acetic acid and. 250M in sodium acetate. what is the ph after addition of. 0050 mol of HCL? what is the ph after the addition of. 0050 mol of NaOH?

Part 2 answer: </span><span>pH = 4.67 </span>
4 0
3 years ago
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