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olchik [2.2K]
2 years ago
13

What is the energy of one photon of red light that has a wavelength of 678 nm?

Chemistry
1 answer:
Vitek1552 [10]2 years ago
5 0

Answer:

E = 2.93×10⁻¹⁹ J

Explanation:

Given data:

Wavelength of photon = 678 nm   (678×10⁻⁹ m)

Energy of photon = ?

Solution:

Formula:

E = h c/λ

h = 6.63×10⁻³⁴ Js

c = 3×10⁸ m/s

E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s / 678×10⁻⁹ m

E = 19.89 ×10⁻²⁶ Jm / 678×10⁻⁹ m

E = 0.0293×10⁻¹⁷ J

E = 2.93×10⁻¹⁹ J

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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 185 L tan
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Answer:

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