<span>Answer:
Some metals have the ability to form differently charged ions. For example, iron can form
2
+
or
3
+
ions. If you simply gave the name iron chloride, you would not know which charge the iron ion possessed.
A Roman numeral is to indicate the charge of the iron.
Iron (
II
) means the iron has a
2
+
charge
Iron (
III
) means that the iron has a
3
+
charge
So, iron (
II
) oxide would have a chemical formula of
FeO
.
(The oxide ion has a
2
â’
charge to balance the
2
+
of the iron to form a neutral compound.)
Iron (
III
) oxide would have a chemical formula of
Fe
2
O
3
(Here you need to find the common multiple of 6, so two iron ions with a
3
+
charge will balance the charge of three oxide ions with a
2
+
charge.)</span>
Answer: In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. If we count the number of hydrogen atoms in the reactants and products, we find two hydrogen atoms.
Answer:
Explanation:
Given:
Ka of HClO2 = 1.1 × 10-2
Ka of HCHO2 = 1.8 × 10-4
Ka of HCN = 4.9 × 10-10
Ka of HNO2 = 4.6 × 10-4
Ka of HF = 3.5 × 10-4
All at a concentration of 0.1 M
A.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HClO2] = 0.1 M
HClO2 --> ClO2^- + H+
1.1 × 10-2 = x^2/0.1
x = sqrt(1.1 × 10^-3
= 0.033 M
pH = -log[H+]
= 1.48
B.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HCHO2] = 0.1 M
HCHO2 --> CHO2^- + H+
1.8 × 10-4 = x^2/0.1
x = sqrt(1.8 × 10^-5)
= 0.0042 M
pH = -log[H+]
= 2.37
C.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HCN] = 0.1 M
HCN --> CN- + H+
4.9 × 10-10 = x^2/0.1
x = sqrt(4.9 × 10-11)
= 0.000007 M
pH = -log[H+]
= 5.16
D.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HNO2] = 0.1 M
HNO2 --> NO2^- + H+
4.6 × 10-4 = x^2/0.1
x = sqrt(4.6 × 10-5)
= 0.0068 M
pH = -log[H+]
= 2.17
E.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HF] = 0.1 M
HF --> F- + H+
3.5 × 10-4 = x^2/0.1
x = sqrt(3.5 × 10-5)
= 0.0059 M
pH = -log[H+]
= 2.23
a) pH = 1.48
b) pH = 2.37
c) pH = 5.16
d) pH = 2.17
e) pH = 2.33
HCN is most basic because;
smallest Ka
Highest pH value = 5.16
At room temperature means in their original state without undergoing any changes.
At room temperature:
milk is liquid
helium is gas
granite is solid
oxygen is gas
steel is solid
gasoline is liquid
Answer:
![5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}](https://tex.z-dn.net/?f=5.31%2A10%5E%7B-10%7D%20%3D%20%5Cfrac%7B%5B%5DH_%7B2%7D%5D%5E%7B2%7D%5BO_%7B2%7D%5D%7D%7B%5BH_%7B2%7DO%5D%5E%7B2%7D%7D)
Explanation:
For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.
For a hypothetical reaction:
xA + yB ⇄ zC
The equilibrium constant is :
![Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }](https://tex.z-dn.net/?f=Keq%20%3D%20%5Cfrac%7B%5BA%5D%5E%7Bx%7D%5BB%5D%5E%7By%7D%7D%7B%5BC%5D%5E%7Bz%7D%20%7D)
The given reaction involves the decomposition of H2O into H2 and O2

The equilibrium constant is expressed as :
![Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}](https://tex.z-dn.net/?f=Keq%20%3D%20%5Cfrac%7B%5B%5DH_%7B2%7D%5D%5E%7B2%7D%5BO_%7B2%7D%5D%7D%7B%5BH_%7B2%7DO%5D%5E%7B2%7D%7D)
Since Keq = 5.31*10^-10
![5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}](https://tex.z-dn.net/?f=5.31%2A10%5E%7B-10%7D%20%3D%20%5Cfrac%7B%5B%5DH_%7B2%7D%5D%5E%7B2%7D%5BO_%7B2%7D%5D%7D%7B%5BH_%7B2%7DO%5D%5E%7B2%7D%7D)