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Ivahew [28]
3 years ago
10

An element has atomic number 10 and an atomic mass of 20. How many neutrons are in the atom of this element? A. 10 B. 20 C. 30 D

. 0 E. 200
Chemistry
1 answer:
MariettaO [177]3 years ago
3 0

Answer : The correct option is, (A) 10

Explanation :

Atomic number : It is defined as the number of protons or number of electrons.  That means,

Atomic number = number of protons = number of electrons

Atomic mass : It is defined as the sum of number of protons and number of neutrons.

Atomic mass = Number of neutrons + Number of protons

As we are given that,

The atomic number of an element = 10

The atomic mass of an element = 20

Now we have to determine the number of neutrons.

Atomic number = number of protons = 10

Atomic mass = Number of neutrons + Number of protons

Number of neutrons = Atomic mass - Number of protons

Number of neutrons = 20 - 10 = 10

Therefore, the number of neutrons are, 10

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How many formula units are in 4.52 moles of H3SO3?<br> Type your answer
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Answer:

The answer is 98.07848. We assume you are converting between grams H2SO4 and mole. You can view more details on each measurement unit: This compound is also known as Sulfuric Acid. The SI base unit for amount of substance is the mole. 1 grams H2SO4 is equal to 0.010195916576195 mole.

<u>Quick conversion chart of moles H2SO3 to grams</u>

1 moles H2SO3 to grams = 82.07908 grams

2 moles H2SO3 to grams = 164.15816 grams

3 moles H2SO3 to grams = 246.23724 grams

4 moles H2SO3 to grams = 328.31632 grams

5 moles H2SO3 to grams = 410.3954 grams

6 moles H2SO3 to grams = 492.47448 grams

7 moles H2SO3 to grams = 574.55356 grams

8 moles H2SO3 to grams = 656.63264 grams

9 moles H2SO3 to grams = 738.71172 grams

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What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
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Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

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