What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
1 answer:
Answer:
The required volume is 1.6 x 10³mL.
Explanation:
When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:
C₁ . V₁ = C₂ . V₂
where,
C₁ and V₁ are the concentration and volume of the concentrated solution
C₂ and V₂ are the concentration and volume of the dilute solution
In this case, we want to find out V₁:
C₁ . V₁ = C₂ . V₂
You might be interested in
Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K
Explanation :
Formula used :
where,
= change in entropy
= change in enthalpy of fusion = 3.17 kJ/mol
As we know that:
= freezing point temperature =
Now put all the given values in the above formula, we get:
Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K