Question

URGENT PLEASE HELP!!!!!!!!!!!! Quadrilateral ABCD ​ is inscribed in a circle.

Answer 1

Opposite angles in a cyclic quadrilateral are equal to 180°.
Therefore,
(4x+5) + (x+15) = 180°
Collect like terms
4x+x+5+15 = 180°
5x+20 = 180
5x = 180-20
5x = 160
$x = \frac{160}{5}$
$x = 32$

A = 4x+5
A = 4(32)+5
= 128+5
= 133°

Answer 2

I got 3.33 because I just set the problem up as

4x+5=x+15

and then I did

4x-x=3x

and then I did

15=3x+5

and then

15-5=10

and then

3x=10

then

10÷3=3.33