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nikklg [1K]
2 years ago
9

The first person to answer this gets brainliest

Mathematics
1 answer:
shusha [124]2 years ago
8 0

Answer:

ok

Step-by-step explanation:

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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
Susan bought a 2 kg bag of grapes on the way home she ate 125 g of the grapes how many grams of grapes that she have left
amid [387]
There are 1,000 grams in a kilogram and she has two kilograms, so there are 2,000 grams. She eats 125 of them so you subtract 125 from 2,000 and you get 1875. She has 1875 grams left of grapes.
4 0
3 years ago
Reba measured a house and its lot and made a scale drawing. She used the scale 9 inches = 7 feet. What is the scale factor of th
Otrada [13]

The scale factor of the Reba's drawing is 9/84, 3/28

Step-by-step explanation:

The scale factor is the ratio between the two corresponding sides of the figure. The point worth noting in computing the scale factor is that both sides must have similar units of dimension while using for comparison purpose.

Given the scale used by Reba is 9 inches to 7 feet

Since both the units are different, we have the option to either convert inches to feet or vice versa

We proceed with converting feet to inches

We know that 1 foot equals to 12 inches. Hence 7 feet would equal 84 inches.

Now scale factor= first dimension/ corresponding dimension

Scale factor= 9/84 which can be reduced to 3/28

4 0
3 years ago
Nadia built a robot to filter air and water efficiently she expects the robot to filter more than 343 liter of air and water whi
crimeas [40]

Step-by-step explanation:

If she is able to achieve her aim, then the robot is very efficient, as it uses as low as 49 joules in filtering 343 litres of air and water.

It will now be a question of what time the robot is able to achieve this feat, if it is able to do it in a time that matches the quality of the work it does, then it will be reasonable to call the robot efficient, and fast too.

7 0
3 years ago
The length of a rectangle is 5 times larger than x. The width is 4 cm less than the length. The perimeter is at least 96 cm. Wha
Ede4ka [16]

We know that the perimeter of a rectangle = 2(l + w)

l = length

w = width

In our problem,

l = 5x

w = 5x - 4

Let's create an inequality to help us solve this problem.

2(5x + (5x - 4)) ≥ 96

Let's start off by simplifying the terms inside the parentheses.

2(10x - 4) ≥ 96

Distribute the 2

20x - 8 ≥ 96

Add 8 to both sides.

20x ≥ 104

Divide both sides by 20

x ≥ 5.2

Let's plug 5.2 into x for our length and width.

Length = 5x = 5(5.2) = 26 cm

Width = 5x - 4 = 5(5.2) - 4 = 26 - 4 = 22 cm

The smallest possible dimensions for the rectangle are, length = 26 cm and width = 22 cm  

6 0
3 years ago
Read 2 more answers
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