The salivary glands, stomach, and pancreas secrete<u> lipase enzymes</u> to break down triglycerides into monoglycerides, fatty acids, and glycerol.
Lipases are a set of water-soluble enzymes that hydrolyze substrates such as triglycerides and phospholipids, have a similar structure and are essential in the metabolism of lipoproteins and lipids.
That is, the function of lipase enzymes is to hydrolyze triglycerides to generate diglycerides, monoglycerides, fatty acids and glycerol.
<u>About lipase enzymes</u>:
- It acts on the neutral fats in the diet, splitting them into triglycerides or diglycerides and these to monoglyceride, which is the most easily absorbed fatty compound.
- The action of lipase is much more manifest on triglyceride, and it is also much faster the higher the molecular weight of the fatty acid present.
- It acts on the surface and in an aqueous medium, the emulsifying agent represented by bile salts is essential for optimum effectiveness.
- They are widely distributed, with a presence in the animal and plant kingdoms and even in the simplest unicellular organisms.
Therefore, we can conclude that the salivary glands, stomach, and pancreas secrete lipase enzymes to break down triglycerides into monoglycerides, fatty acids, and glycerol.
Learn more here: brainly.com/question/15737562
Answer: Prophase
Do check if the answer’s correct, it’s been long since I’ve looked into the stages.
Answer:
Left ventricle.
Explanation:
Human heart is divided into four chambers - two auricles and two ventricles. Heart acts as the pumping organ and carries both oxygenated and deoxygenated blood in the right and left ventricles.
The failure of functioning of any chamber of heart may cause a particular disease in the individuals. The pulmonary congestive heart failure occurs due to the failure of the left ventricles of the heart. The left ventricle carries blood from heart to the body tissues, its failure leads to the backup of blood in the lungs.
Thus, the answer is left ventricle.
It's basically a wave that moves back and forth at regular speed through matter. because of that it transfers energy through a medium (matter). however the movement of the wave is limited because of this but it can still move over long distances. so because of this these types of waves don't move far from their original point or Equilibrium position. in short think of throwing a pebble into water and seeing the little ripples from it, that's a mechanical wave.
Answer:
AaBb × aabb
Explanation:
A test cross is a cross between an unknown genotype (dominant phenotype) with a homozygous recessive genotype in order to discover the actual genotype of the species exhibiting dominant phenotype.
This is because one allele of a gene is capable of masking the expression of another, the allele masking is called DOMINANT allele while the allele being masked is called RECESSIVE allele. The combination of these two alleles is termed heterozygosity.
An organism that is phenotypically dominant for a specific trait may either be heterozygous or homozygous for that gene. For example, a plant gene for tallness with an dominant allele T, and recessive allele t. This plant will need tall if the genotype is TT (homozygous dominant) or Tt (heterozygous dominant). In order to know which of these genotypes the plant actually has, a test cross is conducted.
In this example, two genes A and B are involved. For the first gene, A represents dominant allele while a represents recessive allele. For the second gene, B represents dominant allele while b represents recessive allele.
In a cross involving parents AABB (homozygous dominant for both genes) and aabb (homozygous recessive for both genes), the F1 progeny will all exhibit phenotypic dominance (AaBb).
However, we cannot know the genotype by merely looking at the phenotype. We cannot ascertain yet whether the dominance is heterozygous or homozygous, hence the need for a test cross.
The test cross is between the dominant F1 progeny and a homozygous recessive i.e. AaBb × aabb. Some of the F2 generation will show recessive traits if the unknown genotype is heterozygous.
