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Alexus [3.1K]
3 years ago
8

A subtending arc on a circle with a radius of 4.5 centimeters has an arc length of 8π. The measure of the angle subtended by the

arc is what?
Mathematics
1 answer:
ella [17]3 years ago
3 0
For the answer to the question above, 

<span>the angle of 360 ° → π.d </span>

<span>the angle of x ° → 8π </span>


<span>You make the cross-multiply and you can get: </span>

<span>x * π.d = 8π * 360 </span>

<span>x * d = 8 * 360 </span>

<span>x = 8 * 360/d → where d = 2r </span>

<span>x = 8 * 360/2r </span>

<span>x = 4 * 360/r → where r = 4.5 cm </span>

<span>x = 4 * 360/4.5 </span>

<span>x = 320 °</span>
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Answer:

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Step-by-step explanation:

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Here, it is convenient to use one vertical side of the figure as the base. You can count the grid squares to see that it is 8 units long.

The height is then the distance from one vertical side to the other. Again, you can count the grid squares to see that it is 3 units.

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A = (8 units)·(3 units) = 24 units^2

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The temperature outside dropped 13°F in 7 hours. The final temperature was -2°F. What was the starting temper
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the sum of 3 consecutive integers is 29 less than 5 times the smallest number. find the three numbers
allochka39001 [22]

x + x + 1 + x + 2 = 5x - 29

Combine like terms.

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PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

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2 years ago
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