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Anettt [7]
3 years ago
6

Given f(x)=9-2x, if f(x)=19, find the value of x. Can some one help please?

Mathematics
2 answers:
ruslelena [56]3 years ago
8 0

Answer:

-5=x

Step-by-step explanation:

f(x)=9-2x when f(x)=19

19=9-2x

Subtract 9 from both sides

10= -2x

Divide both sides by -2 to isolate the variable

-5=x

eimsori [14]3 years ago
6 0

Answer: -5

Step-by-step explanation: 19 -9 = 10. 10/-2 = -5

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3 years ago
Of the bundles delivered daily to the store, 1/3
Triss [41]

Answer:

x=9

Step-by-step explanation:

Let total bundle=x

Morning edition of the daily sun=1/3x

=x/3

Afternoon edition of the daily sun=2

That leaves 2x/3 - 2, of which

x/3 - 1 are regional

1 is local

1 from another state

Sum everything

x = x/3 + 2 + x/3 - 1 + 1 + 1

x=2x/3 +3

x-2x/3=3

3x-2x/3=3

x/3=3

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3 0
3 years ago
Where does the normal line to the paraboloid z = x2 + y2 at the point (1, 1, 2) intersect the paraboloid a second time?
Digiron [165]

Answer:

the intersection point is ( -5/4, -5/4, -9/8)

Step-by-step explanation:

F(x,y,z) = x² +y² -z= 0

Then find differential of each terms then we have

∀f(x)=2x

∀f(y)=2y

∀f(z)=-1

The partial differential which is the director vector is at F(x,y,z)= (1,1,2)

Vf(1,1,2) = (2,2,-1)

But the given point is ( 1.1,2)

Then the parametric equation of normal line will be

x= 1+2t

y= 1+2t

z= 2 -t

The parametric equation can be formed as

(1+2t)² + (1+2t)² - (2-t)= 0

If we expand the expression above we have,

2(1+4t+4t²) - 2+t= 0

0= 8t² + 9t

t= 0 or t= -9/8

Substitute the value of t into the parametric equation above

At t=0

x= 1+2t; x= 1+2(0)=1

y= 1+2t; y= 1+2(0)=1

z=2 -t ; z= 2-(0)= 2

At =0 , we have (1,1,2)

At t= -9/8

x= 1+2t; x= 1+2(-9/8)=-5/4

y= 1+2t; y= 1+2(-9/8)=-5/4

z=2 -t ; z= 2-(-9/8)= -9/8

Therefore, the intersection point is ( -5/4, -5/4, -9/8)

4 0
3 years ago
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