All categories

4 years ago

Sin x= 1.5 value of x

Mathematics

1 answer:

alina1380 [7]4 years ago

3 0

Answer:

x = π - sin^(-1)(3/2) + 2 π n_1 for n_1 element Z

or x = 2 π n_2 + sin^(-1)(3/2) for n_2 element Z

Step-by-step explanation:

Solve for x:

sin(x) = 1.5

1.5 = 3/2:

sin(x) = 3/2

Take the inverse sine of both sides:

Answer: x = π - sin^(-1)(3/2) + 2 π n_1 for n_1 element Z

or x = 2 π n_2 + sin^(-1)(3/2) for n_2 element Z

You might be interested in

Bob cycles 5.4 km every morning.how many feet are in 5.4 km, given that 1 mile=1.609 km and 1 mile=5,280 feet?

creativ13 [48]

Answer:

17,720 ft

Step-by-step explanation:

5.4 km * (1 mile)/(1.609 km) * (5280 ft)/(1 mile) = 17,720 ft

5 0

3 years ago

Explain how you would use the number line to solve the following equation. You can write out the fraction names or use the forwa

Dennis_Churaev [7]

Answer: 2

Step-by-step explanation:

1. Convert the mixed numbers to improper fractions,

2. then find the LCD and combine.

4 0

2 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

5 0

3 years ago

Help meeeeeeeeeeeeeee

siniylev [52]

GEF
The middle point aka the E has to be in the middle and then the first and last points don’t matter

4 0

2 years ago

Mathematics challenge

kari74 [83]

Get the equation of the line containing PQ using the point-slope formula:

y - (-2) = 3/2 (x - (-6))

Solve for y to get it in slope-intercept form:

y = 3/2 x + 7

so the y-intercept is (0, 7).

The line containing QR is then

y - 7 = -3/4 (x - 0)

y = -3/4 x + 7

The point R is on the x-axis, so its y-coordinate is 0. Plug in y = 0 and solve for x to get the other coordinate:

0 = -3/4 x + 7

3/4 x = 7

x = 4/3×7 = 28/3

So the point R has coordinates (28/3, 0).

6 0

3 years ago