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romanna [79]
3 years ago
7

Nicholas is at The Noah's Ark Amusement Park and preparing to ride on The Point of No Return racing slide. At the top of the sli

de, Nicholas (m=50 kg) is 28.5 m above the ground. Determine Nicholas' speed as he arrives at the bottom of the slide.
Physics
2 answers:
Kipish [7]3 years ago
6 0
You can not determine the speed based on the information given
Naya [18.7K]3 years ago
6 0

Answer:

Explanation:

Recall that from the principle of conservation of energy,

P.E = K.E -------- eqn i

Solution

P.E = mgh

K.E = \frac{1}{2} mv^{2}

i.e mgh = \frac{1}{2} mv^{2} --------- eqn ii

m = 50 kg

v = ?

g = 9.8 ms^{-2}

h = 28.5 m

substitute for all values in eqn ii

50 X 9.8 X 28.5 = \frac{1}{2} X 50 X v^{2}

13965 = 25 X v^{2}

v^{2}  = \frac{13965}{25}

v^{2} = 558.6

v = \sqrt{558.6}

v = 23.635 m/s

<em>Therefore, Nicholas arrives the bottom of the slide at a speed of 23.635 m/s</em>

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Eddi Din [679]
An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
5 0
3 years ago
A 65-kg skier grips a moving rope that is powered by an engine and is pulled at a constant speed to the top of a 230 hill. The s
Sveta_85 [38]

Answer:

The required power by the engine is 33.0 hp

Explanation:

Solution

Newton's second law says that, the net force Fnet on an object of mass m will accelerates the object

Where

Fnet = ma

a = acceleration

θ = angle of incline,

m = mass of the 30 skiers,

f = frictional force

N = normal force

mg sinθ, mg cos θ are components of weight skier

F = the force applied by engine

Now,

The skier mass  is 65 kg

We calculate the mass of the 30 skier

m = 30 (65kg) = 1950 kg

Calculate the net force acting on the skiers along the x-axis

Fnet, x=ma

Now,

F-mg sin θ - f = 0

F= mg sin θ + f -----(1)

The kinetic frictional force is denoted by

f = μk N ------(2)

μk = The coefficient of the kinetic friction

We now, calculate the net force acting on the skiers along y axis

Fnet, y = ma

N- mg cos θ = 0

so,

N = mg cos θ

This value is  substituted in equation (2)

f = μk mg cos θ

we substitute the value for equation (1)

F = mg sin θ + μk mg cos θ

mg =  sinθ + μk cos θ)-----(3)

The next step is to calculate the work done by the engine in pulling the skiers, the incline top by applying the equation 3

W = Fx

= mg ( sinθ + μk cos θ)x

x = the displacement

we now substitute 1950 kg for m, 23° for θ, 0.10 for μk and 320m for x

so,

W = mg ( sinθ + μk cos θ)x

= (1950 kg) (9.81 m/s²) (sin 23° + (0.10) cos 23°) (320 m)

= 2.99 * 10 ^6 J

Then,

The time from minute to s is converted

t =(2.0min) ( 60sec/1.0min) = 120 sec

Now we calculate the power needed by the engine to pull the skiers at the incline top

Thus,

P = W/t

we substitute  2.955 * 10 ^6 J for W and  120 s for t

we have,

P = 2.955 * 10 ^ 6 J/ 120 s

= ( 2.4625 * 10 ^ 4 W) (1.0 hp/746 W)

= 33.0 hp

In conclusion the required power by the engine is 33.0 hp

3 0
3 years ago
6. Mr. Leppold jumps out of a plane with a parachute...before the chute opens,
polet [3.4K]

1) He has both potential and kinetic energy

2) Before the parachute opens, the potential energy decreases and the kinetic energy increases

Explanation:

1)

The gravitational potential energy of a body is the energy possessed by the object due to its position in a gravitational field, and it is given by:

PE=mgh

where

m is the mass of the body

g is the acceleration of gravity

h is the height of the body above the ground

On the other hand, the kinetic energy of a body is the energy possessed by the body due to its motion; it is given by

KE=\frac{1}{2}mv^2

where

v is the speed of the object

Here Mr. Leppold has both potential and kinetic energy before opening the parachute, because:

- It is moving at a certain speed, so v\neq 0, therefore he has kinetic energy

- He is at a certain height above the ground, h\neq 0, therefore he has potential energy

2)

The total mechanical energy of Mr.Leppold is the sum of the potential and the kinetic energy:

E=PE+KE

According to the law of conservation of energy, in absence of air resistance, this quantity remains constant.

During the fall, the height of Leppold decreases: this means that as h decreases, the potential energy decreases  too.

However, the total energy E must remain constant: therefore, this means that the kinetic energy KE must increase, and this occurs because the speed of Mr. Leppold increases as he falls.

Learn more about kinetic and potential energy:

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brainly.com/question/10770261

#LearnwithBrainly

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Calculate the constant acceleration a in g’s which the catapult of an aircraft carrier must provide to produce a launch velocity
goblinko [34]
The solution to the problem is as follows:

<span>First, I'd convert 188 mi/hr to ft/s. You should end up with about ~275.7 ft/s.
 
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Vinitial = 0 ft/s

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</span>
<span>Now just plug in Vf, Vi and d to solve
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<span>Vf^2 = Vi^2 + 2 a d 

</span><span>BTW: That will give you the acceleration in ft/s^2. You can convert that to "g"s by dividing it by 32 since 1 g is 32 ft/s^2.</span>
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3 years ago
A ray of light bends upon entering a new medium. What is this phenomenon called?
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Refraction is a phenomenon which results when a ray of light enters from one medium to another medium. When a ray of light enters from denser medium to rarer medium, it bends away from the normal. The laws of refraction are: The incident ray, the refracted ray and the normal all lie in the same plane.
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3 years ago
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