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3 years ago

Why does changing the shape of an object have no effect on the density?

1 answer:

7 0

Because the object is still made of the same material
Density is not affected by the weight and shape of an object its affected by how concentrated the atoms are in a given volume

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Question 20

fenix001 [56]

Answer:

(b) Water

Explanation:

The density of the liquid is found by dividing its mass by its volume.

The mass of the liquid is the difference in mass between the full and empty graduated cylinder:

liquid mass = (145 g) -(45 g) = 100 g

<h3>volume</h3>

The cylinder is said to contain 100 mL of the liquid, so that is the volume of interest.

<h3>density</h3>

The ratio of mass to volume is the liquid's density:

ρ = (100 g)/(100 mL) = 1 g/mL

This density identifies the most likely liquid as water.

8 0

2 years ago

People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

fiasKO [112]

Answer:

636.619772368 A

Explanation:

$\tau$ = Torque = $1\times 10^{-3}\ N/m$

B = Magnetic field of Earth = $5\times 10^{-5}\ T$

A = Area

d = Diameter = 20 cm

Current is given by

$I=\dfrac{\tau}{BA}\\\Rightarrow I=\dfrac{1\times 10^{-3}}{5\times 10^{-5}\times \dfrac{\pi}{4}\times 0.2^2}\\\Rightarrow I=636.619772368\ A$

The current is 636.619772368 A

8 0

3 years ago

Which mathematically describes the wave properties of electrons?.

Afina-wow [57]

The Quantum Theory

Hope this helps

8 0

3 years ago

Read 2 more answers

The momentum of an object is determined by the object’s mass and velocity. Which object has more momentum?

Gnesinka [82]

Answer:

You need to give the options but the formula is p=mv

Explanation:

7 0

3 years ago

(I) A novice skier, starting from rest, slides down an icy frictionless 8.0° incline whose vertical height is 105 m. How fast is

Vlad1618 [11]

Answer:

v = 45.37 m/s

Explanation:

Given,

angle of inclination = 8.0°

Vertical height, H = 105 m

Initial K.E. = 0 J

Initial P.E. = m g H

Final PE = 0 J

Final KE = $\dfrac{1}{2}mv^2$

Using Conservation of energy

$KE_i + PE_i + KE_f + PE_f$

$0 + m g H = \dfrac{1}{2}mv^2 + 0$

$v = \sqrt{2gH}$

$v = \sqrt{2\times 9.8 \times 105}$

v = 45.37 m/s

Hence, speed of the skier at the bottom is equal to v = 45.37 m/s

3 0

3 years ago