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juin [17]
3 years ago
6

A potter's wheel rotating at 215 rev/min is switched off and rotates through 75.0 revolutions prior to coming to rest. What is t

he constant angular acceleration of the potter's wheel during this interval
Physics
1 answer:
vaieri [72.5K]3 years ago
6 0

Explanation:

Given :

Initial angular velocity =w_i= 215 rev/min

Final angular velocity =w_f= 0

Number of revolutions=n =75.0 rev

Using relation

w_f^2-w_i^2=2\alpha n

0-215^2=2\times 75\alpha

-308.1666 rev/min^2=\alpha

Converting to rad/s^2

\alpha =-1.45 rad/s^2

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