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juin [17]
3 years ago
6

A potter's wheel rotating at 215 rev/min is switched off and rotates through 75.0 revolutions prior to coming to rest. What is t

he constant angular acceleration of the potter's wheel during this interval
Physics
1 answer:
vaieri [72.5K]3 years ago
6 0

Explanation:

Given :

Initial angular velocity =w_i= 215 rev/min

Final angular velocity =w_f= 0

Number of revolutions=n =75.0 rev

Using relation

w_f^2-w_i^2=2\alpha n

0-215^2=2\times 75\alpha

-308.1666 rev/min^2=\alpha

Converting to rad/s^2

\alpha =-1.45 rad/s^2

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Now we're ready to use the formula that you gave us.  (Thank you.)

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6 0
3 years ago
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Answer:

10.4mm

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3 years ago
An object of mass 30 kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.
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what is the difference between stirring hot soup with a wooden spoon and a metal spoon? what physical property is being observed
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2 years ago
Remember to include your data, equation, and work when solving this problem.
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Answer:

F = 0.00156[N]

Explanation:

We can solve this problem by using Newton's proposed universal gravitation law.

F=G*\frac{m_{1} *m_{2} }{r^{2} } \\

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G = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

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